Answer:
<em>90% confidence interval for the true proportion of men who applied to the nursing program.</em>
<em>(0.09674 ,0.14326)</em>
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given sample size 'n' = 500
sample proportion
Level of significance ∝= 0.90 or 0.10
<em>90% confidence interval for the true proportion of men who applied to the nursing program.</em>
<em></em><em></em>
<em></em><em></em>
<em></em><em></em>
<em>On calculation , we get</em>
<em>( 0.12 - 0.02326 , 0.12 + 0.02326)</em>
<em>(0.09674 ,0.14326)</em>
<u><em>Final answer</em></u><em>:-</em>
<em>90% confidence interval for the true proportion of men who applied to the nursing program.</em>
<em>(0.09674 ,0.14326)</em>
<em></em>
<em></em>
<em></em>