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3 years ago

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Kramer Fabrications stockholders' equity at the beginning of July 2017 was $600,000. During the month, the company earned net in

come of $145,000 and paid dividends of $25,000. At the end of July 2017, what is the amount of stockholders' equity?

1 answer:

Ymorist [56]3 years ago

4 0

Answer:

$720,000

Step-by-step explanation:

As per the question,

Kramer Fabrications stockholders' equity at the beginning of July 2017

Stockholders' equity = $600,000

Net income earned = $145,000

Dividends paid = $25,000

Stockholders' equity at the end of of July 2017

= Net income - Dividend + Stockholders’ Equity

= $145,000 - $25,000 + $600,000

= $720,000

Therefore,

The amount of stockholders' equity at the end of of July 2017 = $720,000.

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svet-max [94.6K]

Answer:

Given the statement: Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P.

Properties of Kite:

The diagonals are perpendicular

Two disjoint pairs of consecutive sides are congruent by definition of kite

One diagonal is the perpendicular bisector to the other diagonal.

It is given that: Side QR = 5m and diagonal QS = 6m.

Then, by properties of kite:

$QP = \frac{1}{2}QS$

Substitute the value of QS we get QP;

$QP = \frac{1}{2}(6)$ = 3 m

Now, in right angle $\triangle RPQ$

Using Pythagoras theorem:

$QR^2= RP^2 +QP^2$

Substitute the given values we get;

$(5)^2= RP^2 +(3)^2$

or

$25= RP^2 +9$

Subtract 9 from both sides we get;

$16= RP^2$

Simplify:

$RP = \sqrt{16} = 4 m$

Therefore, the length of segment RP is, 4m

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2 years ago

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Which linear inequality is represented by the graph? (A)y ≤1/3 x − 1 (B)y ≥ x − 1 (C)y < 3x − 1 (D)y > 3x − 1

lubasha [3.4K]

The equation of the line is $\boxed{y \geqslant \frac{1}{3}x - 1}.$

Further explanation:

The linear equation with slope $m$ and intercept $c$ is given as follows.

$\boxed{y = mx + c}$

The formula for slope of line with points $\left( {{x_1},{y_1}} \right)$ and $\left( {{x_2},{y_2}} \right)$ can be expressed as,

$\boxed{m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}}$

Given:

Explanation:

The line intersects y-axis at $\left( {0, - 1} \right)$ . Therefore, the y-intercept is $-1.$

The line passes through the points $\left( {0, - 1} \right)$ and $\left( {3,0} \right).$

The slope can be obtained as follows,

$\begin{aligned}m&= \frac{{0- \left( {- 1} \right)}}{{3 - 0}}\\&= \frac{1}{3}\\\end{aligned}$

Substitute $\dfrac{1}{3}$ for m, $3$ for $x$ and $0$ for $y$ in equation $y = mx + c$ to obtain the value of $c$ .

$\begin{aligned}0& \frac{1}{3} \cdot 3 + c\\- 1&=c\\\end{aligned}$

To check whether the equation includes origin substitute 0 for x and 0 for y in equation $y \geqslant \dfrac{1}{3}x - 1.$

$\begin{aligned}0&\geqslant \frac{1}{3} \times 0 - 1 \\0&\geqslant - 1\\\end{gathered}$

The statement is true. The equation contains origin.

The equation of the line is $\boxed{y \geqslant \frac{1}{3}x - 1}.$

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear equation

Keywords: numbers,slope, slope intercept, inequality, equation, linear inequality, shaded region, y-intercept, graph, representation, origin.

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