A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?
1 answer:
Answer:
6 and 10
Step-by-step explanation:
xy=60
2(x+y)=32
x+y=16
y=16-x
Substitute y into area equation
x(16-x)=60
16x-x^2=60
x^2-16x+60=0
(x-10)(x-6)=0
x=10, 6
y=6, 10
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C. 20
