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stepladder [879]
2 years ago
14

A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?

Mathematics
1 answer:
Dominik [7]2 years ago
6 0

Answer:

6 and 10

Step-by-step explanation:

xy=60

2(x+y)=32

x+y=16

y=16-x

Substitute y into area equation

x(16-x)=60

16x-x^2=60

x^2-16x+60=0

(x-10)(x-6)=0

x=10, 6

y=6, 10

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Elden [556K]

Answer:

no b 11 sq.units is the answer

3 0
2 years ago
(-2x+3y=8....(i)<br>( x+y=2.........(ii)<br>solve by elumination method and substitution​
yan [13]

Answer:

 x = -2/5

 y = 12/5

Step-by-step explanation:

Substitution method;

-2x + 3y = 8  -----------(i)

x + y =2   -----------(ii)

x = 2 - y

substitute the value of x in equ (i)

  (-2)* (2-y) + 3y = 8

     -4 + 2y + 3y = 8

                   5y = 8 + 4

                     y = 12/5

substitute the value of y in equ (ii)

x + 12/5 = 2

        x = 2 - 12/5

           = 2*5/1*5 - 12/5  

          = 10 -12/5 = -2/5

Ans: x = -2/5

       y = 12/5

elimination method:

-2x + 3y = 8  -----------(i)

x + y =2   -----------(ii)

                                    (i)   ====>    -2x + 3y = 8

multiply equ (ii) by 2         ====>    <u>  2x + 2y = 4</u>

             add (i) and (ii)                             5y = 12

                                                                   y = 12/5

Substitute in equ (ii)

x + 12/5 = 2

        x = 2 - 12/5

           = 2*5/1*5 - 12/5  

          = 10 -12/5 = -2/5

Ans: x = -2/5

       y = 12/5

                                                       

               

5 0
3 years ago
Read 2 more answers
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Crank

Answer:

y=40

Step-by-step explanation:

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