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Paha777 [63]
3 years ago
8

There are 150 marigold plants in a back yard. Each month, the number of marigold plants decreases by 15%. There are 125 sunflowe

r plants in the back yard. Each month, 8 sunflower plants are removed.
Part A: Write functions to represent the number of marigold plants and the number of sunflower plants in the back yard throughout the months. (4 points)

Part B: How many marigold plants are in the back yard after 3 months? How many sunflower plants are in the back yard after the same number of months? (2 points)

Part C: After approximately how many months is the number of marigold plants and the number of sunflower plants the same? Justify your answer mathematically. (4 points)
Mathematics
1 answer:
Lelu [443]3 years ago
8 0
For the marigolds 
M  = 150(0.85)^x     where x is the number of months
For sunflowers 
S = 125 - 8x  where x = number of months

Part B
after 3 months there are 150(0.85)^3  =  92 marigolds

after 3 moths there are 123 -  8*3 = 99 sunflowers

Part C 

There are the same number of plants when  the 2 functions are equal:-

So we have  150(0.85)^x = 125 - 8x
solving this for x is not straight forward . it could be done by drawing 2 graphs and seeing where they intersect.

They come close to being equal after 2 months and after 14 months

Check out the graph on
www.desmos.com/calculator/i3m55hb2i3
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if (-1) ⇒ -3*(1)=-3 ⇒ answer: (-1;-3)
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7 0
3 years ago
∆ABC has A(-3, 6), B(2, 1), and C(9, 5) as its vertices. The length of side AB is units. The length of side BC is units. The len
leonid [27]

Answer:

AB = 7.07 units

BC = 8.06 units

AC = 12.04 units

Step-by-step explanation:

To find the length for each side of the triangle, apply the distance formula between each pair of vertices.

<u>AB</u>

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(2--3)^2 + (1-6)^2} \\d = \sqrt{(5)^2 + (-5)^2} \\d = \sqrt{25 + 25} \\d = \sqrt{50} \\d=7.07

<u />

<u>BC</u>

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9-2)^2 + (5-1)^2} \\d = \sqrt{(7)^2 + (4)^2} \\d = \sqrt{49 + 16} \\d = \sqrt{65} \\d=8.06

<u />

<u>AC</u>

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9--3)^2 + (5-6)^2} \\d = \sqrt{(12)^2 + (-1)^2} \\d = \sqrt{144 + 1} \\d = \sqrt{145} \\d=12.04

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nikitadnepr [17]

Answer:

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Step-by-step explanation:

using the pythagorean theorem, c^2=a^2+b^2

5^2=x^2+4^2, x=3

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A female cockroach can produce 80 offspring at a time. If half are female, and each female produces 80 offspring, how many cockr
IRINA_888 [86]
Ok if half are female that means 40 than 80 more for each of them because they all produce 80 so 80  times 40  = 3200 your gonna do the same 2 more times because of 3 generations so 3200 times 3 = 9600 in total

3 0
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the answer for this question is option b

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