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3 years ago

N/N-3 = 2/3 please find N

Mathematics

2 answers:

gregori [183]3 years ago

8 0

Answer:

N is -6

Step-by-step explanation:

1. You could cross multiply the n/n-3 and 2/3

2. To cross multiply , you would multiply n times 3 and n-3 times 2

3. After cross multiplying you would get the equation of 3n=2n-6

4. You subtract 2n on both sides of the equal side, making the equation 1n=-6

5. 1n is N , and N is equal to -6, which is the answer

SOVA2 [1]3 years ago

7 0

Answer:

N = -6

Step-by-step explanation:

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What is the completely factored form of p4 – 16? (p – 2)(p – 2)(p 2)(p 2) (p – 2)(p – 2)(p – 2)(p – 2) (p minus 2) (p 2) (p squa

n200080 [17]

The completely factored form of the provided polynomial is (p -2) (p+ 2) (p² +4). The option 4 is the correct option.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is a real number).

The polynomial equation given in the problem is,

$p^4 - 16$

Let the factor form of the polynomial is f(p). Thus,

$f(p)=p^4 - 16\\f(p)=p^4 - 2^4\\f(p)=(p^2)^2- (2^2)^2$

Using the formula of difference of squares, we get,

$f(p)=(p^2-4)(p^2+4)\\f(p)=(p^2-2^2)(p^2+4)\\f(p)=(p-2)(p+2)(p^2+4)$

Thus, the completely factored form of the provided polynomial is (p -2) (p+ 2) (p² +4). The option 4 is the correct option.

Learn more about polynomial here;

brainly.com/question/24380382

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2 years ago

Which expressions are equivalent when m = 1 and m = 4?

s344n2d4d5 [400]

Answer:

expression 2

Step-by-step explanation:

<h2><u>Which expressions are equivalent when m = 1 and m = 4?</u></h2>

<h3><u>first expression:</u></h3>

5m -3 and 2m + 5 + m

when m = 1

5(1) - 3 = 2 and 2(1) + 5 + 1 = 8

and m = 4

5(4) -3 =23 and 2(4) + 5 + 4 = 17

<u>expression 1 IS</u><u> NOT EQUIVALENT</u><u> </u>

<h3><u>second expression :</u></h3>

3 m + 4 and m + 4 + 2 m

when m = 1

3 (1) + 4 = 7 and 1 + 4 +2 (1) = 7

and m = 4

3 (4) + 4 = 16 and 4 + 4 +2 (4) = 16

expression 2 <u>IS EQUIVALENT </u>

<h3><u>third expression :</u></h3>

2 m + 7 and 3 m - 3 + m

when m = 1

2(1) + 7 = 9 and 3(1) -3 + 1 = 1

and m = 4

2(4) + 7 = 15 and 3(4) -3 + 4 = 13

expression 3 IS <u>NOT EQUIVALENT</u>

<h3><u>fourth expression :</u></h3>

5 m + 3 and 4 m + 2 + 2 m

when m = 1

5(1)+ 3 = 8 and 4(1) + 2 +2(1) = 8

and m = 4

5(4)+ 3 = 23 and 4(4) + 2 +2(4) = 26

expression 4 is <u>NOT EQUIVALENT </u>

the expression that is <u><em>EXPRESSION 2 </em></u>

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3 years ago

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Y=10x+2<br> y=8x+2x+2<br> How many solutions

Luba_88 [7]

Simplify y=8x+2x+2: y=10x+2
Same as equation y=10x+2
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3 years ago

A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company prod

tekilochka [14]

Answer:

C) 515 hours.

D) 500 hours

c) sample 3

Step-by-step explanation:

1. Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample Service Life (hours)

1 2 3

495 525 470

500 515 480

505 505 460

x1`= ∑x1/n1= 2000/4= 500 hours

x2`= ∑x2/n2= 2060/4= 515 hours

x3`= ∑x3/n3= 1880/4= 470 hours

2. The mean of the sampling distribution of sample means for whenever service life is in control is 500 hours . It is the given mean in the question and the limits are determined by using μ ± σ , μ±2 σ or μ ± 3 σ.

In this question the limits are determined by using μ ± σ .

3. Upper control limit = UCL = 520 hours

Lower Control Limit= LCL = 480 Hours

Sample 1 mean = x1`= ∑x1/n1= 2000/4= 500 hours

Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample 3 mean = x3`= ∑x3/n3= 1880/4= 470 hours

This means that the sample mean must lie within the range 480-520 hours but sample 3 has a mean of 470 which is out of the given limit.

We see that the sample 3 mean is lower than the LCL. The other two means are within the given UCL and LCL.

This can be shown by the diagram.

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2 years ago

Solve for y 3x+6y=30

balandron [24]

Answer:

the answer= y=5−x/2

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2 years ago

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