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julsineya [31]
2 years ago
10

Ii

Mathematics
1 answer:
weqwewe [10]2 years ago
8 0

Answer:

i think you did not type in the whole sentence you stopped at are

Step-by-step explanation:

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Given: AB ≅ BC , m∠MOC = 135° OM − angle bisector of ∠AOB Prove: ∠ABO ≅ ∠CBO
Gennadij [26K]

Answer:

See explanation

Step-by-step explanation:

1. Angles AOM and MOC are supplementry angles. If m∠MOC = 135°, then

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2. OM − angle bisector of ∠AOB, then

m∠AOM = m∠MOB = 45°

3. Now

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m∠BOC = 135° - 45° = 90°

4. Since m∠BOC = 90°, BO is perpendicular to AC.

5. Consider isosceles triangle ABC (because AB ≅ BC). BO is the height drawn to the base, so it is an angle B bisector too, thus

∠ABO ≅ ∠CBO

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Step-by-step explanation:

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