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Vladimir [108]
3 years ago
14

X 3 + 14x 2 + 59x + 70 = (x + 2)(x + 5)(x + a0)

Mathematics
2 answers:
Klio2033 [76]3 years ago
5 0
A0 = 7 because 2 * 5 * 7 = 70

erma4kov [3.2K]3 years ago
5 0

Answer:

7

Step-by-step explanation:

x^3 + 14x^2 + 59x + 70 = (x + 2)(x + 5)(x + a_0)

Here a0 is a constant

To find the value of a0 we multiply all the constant terms and make it equal to constant 70

2 times 5 times a0  is 10a_0

10a_0=70

Divide both sides by 10

a_0= 7

So, the value of a_0 is 7

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In the figure to the right, AB = 7 1/2 m, BC = 2 1/4 m, and DE = 1 1/4 m. Find the perimeter of the figure if all angles are rig
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Answer:

Perimeter=22 m

Step-by-step explanation:

Perimeter Of A Figure

Perimeter is the distance measured around a shape. If the figure is line-shaped, the perimeter can be obtained by adding the individual lengths of each segment around the shape.

The figure shown is surrounded by line segments. We only have to add them all to find the perimeter. But we don't need each individual length to do so. We may notice the following (given all angles are right):

The sum of HG+FE+DC equals AB. So the upper and lower lengths are twice AB, or equivalently: 2*7 1/2 m =15 m

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3 years ago
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Answer:

\boxed{a_n \:  =  \: 64 \:  \times  \: ( -  \frac{3}{4} ) ^{n \:  -  \: 1} }

Step-by-step explanation:

  • We first compute the ratio of this geometric sequence.

r \:  =  \:  \frac{ - 48}{64}  \\  \\ r   \:  =  \:  \frac{36}{ - 48}  \\  \\  r \:  =  \:  \frac{ - 27}{36}

  • We simplify the fractions:

r \:  =  \:   -  \frac{3 }{4}   \\  \\ r   \:  =  \:   -  \frac{3 }{4}  \\  \\  r \:  =  \:    -  \frac{3 }{4}

  • We deduce that it is the common ratio because it is the same between each pair.

r \:  =  \:  -  \frac{3 }{4}

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a_1 \:  =  \: 64; \: r \:  =  \:  -  \frac{3 }{4}

<h3>We apply the data in this formula:</h3>

\boxed{a_n \:  =  \: a_1 \:   \times  \:  {r}^{ n \:  -  \: 1} }

_______________________

<h3>We apply:</h3>

\boxed {\bold{a_n \:  =  \: 64 \:   \times  \:  {( -  \frac{3}{4} )}^{ n \:  -  \: 1} }}

<u>Data</u>: The unknown "n" is the term you want

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<em>Hope This Helps!!!</em>

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