HELP ASAP PLS GETTING TIMED

Rachel types

Art [367]

Answer:

4 im pretty sur

Step-by-step explanation:

7 0

3 years ago

Hello can you please help me posted picture of question

loris [4]

The sample space will be: {1, 2, 3, 4, 5, 6}

Event A is: {Rolling 1,2 or 3}

Complement of event A will contain all those outcomes in the sample space which are not a part of event A.

So, complement of event A will be: {Rolling a 4,5 or 6}

Thus option A gives the correct answer

3 0

3 years ago

An oil exploration firm is formed with enough capital to finance ten explorations. The probabil- ity of a particular exploration

tensa zangetsu [6.8K]

Answer:

μ = 1 The firm expects that one oil exploration will be successful.

v(x)= 0.9

Step-by-step explanation:

The first step is to define the random variable x as:

x: number of oil explorations being succesful

Then x can be take this values:

x = 0 , x =1 ... x =10

x is a binomially distributed random variable with parameters.

p = 0.1 and n=10

And the mean or the expected value of x is:

μ = E(x) = np

Then μ = 10*0.1 = 1

And the variance of x is:

V(x) = np(1-p)

V(x) = 10(0.1)(1-0.1)= 0.9

6 0

3 years ago

This i forgot and i need help fast can someone please help.. I will give brainliest

GalinKa [24]

Answer:

1.) 471.24

2.) 1231.5

3.) 113.1

Step-by-step explanation: A = pi x r^2 + pi x r x ^2

1.) a = 3.14 x (5)^2 + 3.14 x 5 x ^2

a = 3.14 x 25 + 3.14 x 5 x 25

a = 78.54 + 392.70

a ≈ 471.24

2.) A = 3.14 (7)^2 + 3.14 x (7) x ^2

a = 3.14 x 49 + 3.14 x 7 x 49

a = 153.93 + 1077.57

a ≈ 1231.5

3.) a = 3.14 (3)^2 + 3.14 x 3 x ^2

a = 3.14 x 9 + 3.14 x 3 x 9

a = 28.27 + 84.82

a ≈ 113.1

3 0

3 years ago

Read 2 more answers

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find h'(x)
h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

 h'(x) = 1.44 ------------ > not exist

8 0

3 years ago