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Rudik [331]
3 years ago
13

SOMEONE PLS HELP WILL GIVE BRAINLIEST ANSWER IF CORRECT

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0
Complementary angles add up to 90°
and supplementary angles add up to 180°

Add the two angles together
82+98=180
So the measure of these two angles are supplementary
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Help me pls. So what is 8y-I​
adell [148]

Answer:

In this problem, "y" represents the integer that must be found or figured for. When a number and a representation are written this way, i.e. "8y", you must mulitply them. If there is more information, you can figure for "y". If there is no other information, "y" is simplied and the end result is "8y".

And I not sure what - 1 is but it might be subtraction.

3 0
3 years ago
PLEASE HELP!!
erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}

3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
8 0
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JulsSmile [24]
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Question 4 0
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. There is not convincing evidence that defensive players can bench-press more weight, on average, than offensive players.

Step-by-step explanation:

Since P>a we can not reject the null hypothesis. We cannot conclude the alternative hypothesis in context.

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Sergio039 [100]

Answer:

3

Step-by-step explanation:

Your answer is 3

8 0
3 years ago
Read 2 more answers
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