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3 years ago

Which function of x has the least value for the y-intercept?

Mathematics

1 answer:

makkiz [27]3 years ago

6 0

It would be option 2 because -3 is the lowest value and y=Mx+b b is the y intercept

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9a + 8 - 20-3-50 Answer

dem82 [27]

Answer:

9a-65

Step-by-step explanation:

simply write 9a+(add the remaining numbers all together)

5 0

3 years ago

Hurricane winds can be as strong as 150 miles per hours. If stick carried by a hurricane wind is flying at 130 mph, how far ( in

slavikrds [6]

Answer:

I believe it's 6.5 hours

Step-by-step explanation:

130/20=6.5

Not sure tho.

3 0

2 years ago

Read 2 more answers

when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%

Fynjy0 [20]

She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%

Selling price = cost price - discount ⇒ discount case
Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = $\frac{160}{90}=\frac{16}{9}$

∵ She sold them with discount 20%

∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = $\frac{20}{100}$ × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

- Equate 0.8x by $\frac{16}{9}$ to find x

∵ 0.8x = $\frac{16}{9}$

- Divide both sides by 0.8

∴ x = $\frac{20}{9}$

Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is $\frac{20}{9}$

- Find 20% of $\frac{20}{9}$

∵ Profit = 20% × $\frac{20}{9}$ = $\frac{20}{100}.\frac{20}{9}=\frac{4}{9}$

- Add $\frac{4}{9}$ to cost price to find the selling price

∴ The selling price of an orange = $\frac{20}{9}$ + $\frac{4}{9}$

∴ The selling price of an orange = $\frac{24}{9}$

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ $\frac{24}{9}$

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

4 0

3 years ago

(x^2y+e^x)dx-x^2dy=0

klio [65]

It looks like the differential equation is

$\left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0$

Check for exactness:

$\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x$

As is, the DE is not exact, so let's try to find an integrating factor µ(x, y) such that

$\mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0$

*is* exact. If this modified DE is exact, then

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}$

We have

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu$

Notice that if we let µ(x, y) = µ(x) be independent of y, then ∂µ/∂y = 0 and we can solve for µ :

$x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}$