Given:
The area model.
To find:
The area as a sum and area as a product.
Solution:
The four terms of the area model are
.
The area as a sum is the sum of all the terms of given area model.
Area as a sum = 
= 
The area as a product is the factor form of sum of all the terms of given area model.
Area as a product = 
= 
= 
Therefore, the area as a sum is
and the area as a product is
.
Answers:
15) x = 8, 
16) x = 9,
, 
17) x = 6,
, 
<u>Step-by-step explanation:</u>
15x³ - 119x² - 10x + 16 = 0

So, the possible rational roots are: +/- 
Use synthetic division with each one until you find a remainder of zero. I am not going to go through each one because it is too time consuming, however, the first one that works is x = 8
(x - 8)(15x² + x - 2)
Next, factor 15x² + x - 2 using any method
(x - 8)(3x - 1)(5x + 2)
Now, solve for x.
x = 8, x =
, x = 
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For #16 & 17, follow the same process as above.
Answer:
it is greater by ten times.