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Kryger [21]
3 years ago
12

What is the difference between 179 and 320

Mathematics
1 answer:
borishaifa [10]3 years ago
7 0
Um... the answer is 141.
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What is all of this <br> Identify ALL sets of parallel and perpendicular lines in this image.
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<u>Parallel lines</u> are lines that run side-by-side without touching or intersecting!

<u>Perpendicular lines</u> intersect/cross and can also make 90° angles (those little green boxes in the picture) in their corners!

Sets of parallel lines:

  • CD and EF

Sets of perpendicular lines:

  • CD and AB
  • EF and AB
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2 years ago
Imagine you are painting a series of towers built from cubes. You are going to paint only the exposed faces of the cubes. What i
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A. Because the paint depends of the cubes
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3 years ago
An insurance company has 25,000 automobile policy holders. If the yearly claim of a policy holder is a random variable with mean
telo118 [61]

Answer:

P(T>8300000)=1-P(T

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Data given

n = 25000 represent the automobile policy holders

\mu= 320 represent the population mean

\sigma =540 represent the population standard deviation

Let T the variable that represent the total of interest on this case. We can assume that the random variable for an individual policy holder is given by:

X\sim N(\mu = 540, \sigma=540)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

First we need to find the distribution for the random variable T like this:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

And the total T is given by:

T=\sum_{i=1}^n X_i =n \bar X

We can find the expected value, variance and deviation for this random variable like this:

E(T)= n E(\bar X) = n \mu = 25000*320=8000000

Var(T)= Var(n\bar X)= n^2 Var(\bar X) = n^2 \frac{\sigma^2}{n}=n \sigma^2 =25000*(540^2)=7290000000

Sd(T)=\sqrt{7290000000}=85381.497

And we are interested on this probability:

P(T>8300000)

And we can use the Z score formula given by:

Z=\frac{T-E(T)}{\sigma_T}

P(T>8300000)=1-P(T

6 0
3 years ago
Find the product of each sum and difference. (2l + 9)(2l – 9)
Alex787 [66]

Answer:

360

Step-by-step explanation:

(i think that is a 1 not an L)

21 + 9 equals 30. And 21-9 equals 12. So you would multiply 30*12 which gives you your answer!

<h2>360</h2>
4 0
2 years ago
What is the probability of the spinner landing on 1 or 3
yan [13]

Answer:

Assuming there are 3 possibilities for the spinner, the answer is \frac{2}{3}

Step-by-step explanation:

7 0
2 years ago
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