Answer:
We conclude that If a function has a vertical asymptote at a certain x-value, then the function is undefined at the value.
Step-by-step explanation:
If a function has a vertical asymptote at a certain x-value, then the function is undefined at the value.
For example, let the function
It is clear that the given function becomes undefined at x = 3 in the denominator.
i.e. 3-3 = 0
It means, the function can not have x = 3, otherwise, the function will become undefined.
In other words, if the function has a vertical asymptote at x = 3, then the function is undefined at the value.
Therefore, we conclude that If a function has a vertical asymptote at a certain x-value, then the function is undefined at the value.
If Andy has 102 coins mixed with dimes and quarters and monetary value of $17.10 then he has 56 dimes and 42 quarters.
Given number of coins Andy has is 102 and montary value of all coins is $17.10.
We have to determine number of dimes and quarters.
1 dime=$0.10
1 quarter=$0.25
Suppose the number of dimes be x and number of quarters be y.
The equations are:
0.10x+0.25y=17.10------------1
x+y=102-------------2
from equation 2, y=102-x
Put the value of y=102-x in equation 1
0.10x+0.25(102-x)=17.10
0.10x+25.5-0.25x=17.10
-0.15x=17.10-25.5
-0.15x=-8.4
x=8.4/0.15
x=56
Put the value of x in y=102-x
y=102-56
y=46
Hence Andy has 56 number of dimes and 46 quarters.
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The function
... f(x) = (x+2)/(x-1) = 1 + 3/(x-1)
is symmetrical about the line y=x, hence is its own inverse.
We can evaluate the desired derivative directly.
... f'(x) -3/(x-1)²
so f'(2) is
... f'(2) = -3/(2-1)²
Answer:
D and B
Step-by-step explanation:
the angles subtract and the other starts and loops
Answer:
1/15
Step-by-step explanation:
Ms. Fox loves to eat cereal and she notices that she only has 1/3 of the box of cereal left. If she spread that amount across 5 days, how much cereal will she have for each day?
The amount of cereal she would have per day is calculated as:
5 days = 1/3 of the box
1 day = x
Cross Multiply
5 days × x = 1 day × 1/3 of the box
x = 1/3 ÷ 5
x = 1/3 × 1/5
x = 1/15 of the box
