Can anyone help me with this?

Mathematics

2 answers:

kolbaska11 [484]3 years ago

5 0

Pretty sure the correct is B

arsen [322]3 years ago

4 0

Answer :The answer is B.

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What is the x and y intercept of 2.5x+8y=240 please show your work.

a_sh-v [17]

Answer:

The x and y intercept are (96,30)

Step-by-step explanation:

8y=240-2.5x

y=240/8-2.5x/8

y=30-0.3125x

The y intercept=30

The x intercept=96 thus 30=0.3125x,x=30/0.3125

5 0

3 years ago

Need some help with indefinite integrals pleasee

goldenfox [79]

Observe that $(x^2+2x+2)'=2x+2$ .

You have that $\int \frac{2x}{x^2+2x+2}\; dx=\int \frac{2x+2-2}{x^2+2x+2}\; dx=\int \frac{2x+2}{x^2+2x+2}\; dx+\int \frac{1}{x^2+2x+2}\; dx=I_1+2I_2$ .

To compute $I_1$ you set $y=x^2+2x+2$ , so $dy=2x+2\; dx$ . Therefore, $I_1=\int \frac{1}{y}\; dy=\ln |y|=\ln |x^2+2x+2|=\ln (x^2+2x+2)$ .

For $I_2$ observe that $x^2+2x+2=(x+1)^2+1$ . Let $y=x+1$ . Then $dy=dx$ and $I_2=\int \frac{1}{y^2+1}=\arctan y=\arctan (x+1)$ .

So, $\int \frac{2x}{x^2+2x+2}=\ln (x^2+2x+2)+2\arctan (x+1)+c$ .