Answer:
1
Step-by-step explanation:
I know for sure
(t-1)(t+1) = t^2-1 through the difference of squares rule
So,
(t-1)(t+1)(t^2+1)
(t^2-1)(t^2+1)
(x-1)(x+1) ... let x = t^2
x^2-1 .... another application of the difference of squares rule
(t^2)^2 - 1... plug in x = t^2
t^4 - 1
2x-3=7
2x=7+3
2x=10
x=10:2
x=5
Have a nice day!! ^^
Answer:
a=3 b=3 and are parrelell
Step-by-step explanation: