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vlada-n [284]
2 years ago
5

Elliott is counting the change from a class fundraiser. He has half as many quarters as nickels, and he has 7 fewer dimes than n

ickels. The total value of coins is $5.90. He wrote the equation 0.10 (7 minus x) + 0.5 (x) + 0.25 (one-half x) = 5.90. Which statements identify Elliott’s errors? Check all that apply.
He should have written the expression for the number of dimes as x – 7.
He should have written the coin values as 5, 10, and 25 and not as 0.5, 0.10, and 0.25.
He should have written the coin value for the nickel as 0.05.
He should have translated the scenario as value of all dimes = value of all nickels and value of all quarters = value of all nickels.
He should have written the expression for number of nickels as 2x.
Mathematics
2 answers:
Akimi4 [234]2 years ago
5 0

Answer: He should have  translated the scenario as value of all dimes = value of all

Step-by-step explanation:

СукаBlyat
2 years ago
its only 1 answer tho, the question asks for 2 errors
azamat2 years ago
3 0
He should’ve translated the scenario as value of all dimes= value of all
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dsp73

Answer:

\boxed{ \bold{ \huge{ \sf{x = 29}}}}

Step-by-step explanation:

\sf{ - 3(3 + x) + 4(x - 6) =  - 4 }

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Similarly, Distribute 4 through the parentheses

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Collect like terms

⇒\sf{x - 9 - 24 =  - 4}

Calculate

⇒\sf{x - 33 =  - 4}

Move 33 to right hand side and change it's sign

⇒\sf{x =  -  4 + 33}

Calculate

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Hope I helped!

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