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stepan [7]
3 years ago
8

A student receives test scores of 62, 83, and 91. The student's final exam score is 88 and homework score is 76. Each test is wo

rth 20% of the final grade, the final exam is 25% of the final grade, and the homework grade is 15% of the final grade. What is the student's mean score in the class?
Mathematics
1 answer:
Alborosie3 years ago
7 0

Answer:

The student's mean score in the class is 80.6

Step-by-step explanation:

we know that

To find out the student's mean score in the class, multiply each score by its worth and adds the numbers

(62+83+91)0.20+(88)0.25+(76).15=80.6

therefore

The student's mean score in the class is 80.6

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3 years ago
A 51-foot wire running from the top of a tent pole to the ground makes an angle of 58° with the ground. If the length of the ten
AfilCa [17]

Answer:

<em>35.11 ft</em>

<em></em>

Step-by-step explanation:

This given situation can be thought of as triangle \triangle PQR where PQ is the length of pole.

PR is the length of rope.

and QR is the distance of bottom of pole to the point of fastening of rope to the ground.

And \angle Q \neq 90^\circ

Given that:

PQ = 44 ft

PR = 51 ft

\angle R = 58^\circ

To find:

Side QR = ?

Solution:

We can apply Sine Rule here to find the unknown side.

Sine Rule:

\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}

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c is the side opposite to \angle C

\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ

Now,

\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ

Let us use the Sine rule again:

\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft

So, the answer is <em>35.11 ft</em>.

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3 years ago
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Answer:

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Step-by-step explanation:

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I believe the third option is correct!

{(-5,1), (-3,2), (-1,3), (1,4), (3,5)}

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