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bulgar [2K]
3 years ago
12

Find the length of the side

Mathematics
1 answer:
MrRa [10]3 years ago
7 0

Answer:

So AC = 25

Step-by-step explanation:

ABC = LMN

That means AB = LM

                    BC = MN

                    AC = LN

We know AB = 41  MN = 38  and LN  = 25

AB = LM = 41

BC = MN=38

AC = LN=25

So AC = 25

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[PEOPLE WITH ALLERGIES]
xeze [42]

Answer:

I have super sensitive skin and one time I used fancy lotion and I broke out completely. It was embarrassing because you could see dots all over my face.

Step-by-step explanation:

6 0
3 years ago
Solve the equation:<br> 5|2x-7|=20
MA_775_DIABLO [31]

Answer:

x = \frac{11}{2}, \frac{3}{2}

Step-by-step explanation:

First, isolate the absolute value:

5|2x - 7| = 20

divide both sides by 5:

|2x - 7| = 4

break into 2 equations:

2x - 7 = 4, 2x - 7 = -4

solve both equations and collect solutions:

2x = 11, 2x = 3

x = \frac{11}{2}, \frac{3}{2}

6 0
3 years ago
Read 2 more answers
Determine the equation of the line passing through the points <br> (4,-1) and (-2,-4)
jenyasd209 [6]

Answer:

y = 1/2x - 3

Step-by-step explanation:

the slope:

m=\frac{-4-(-1)}{-2-4} =\frac{-4+1}{-6} =\frac{-3}{-6} =\frac{3}{6} =\frac{1}{2}

the equation:

with the point (4, -1)

y-(-1)=\frac{1}{2} (x-4)

y+1=\frac{1}{2}x-2

y=\frac{1}{2} x-2-1

y=\frac{1}{2} x-3

I hope this help you

8 0
3 years ago
WILL GIVE BRAINLIEST: What is the local minimum value of the function g(x)=x^4-5x^2+4? (Round answer to the nearest hundredth)
IrinaK [193]

Answer:

Step-by-step explanation:

you can find where the first derivative is 0 to find the critical points

g'(x) = ( x^4 -5x^2 +4)' = 4x³-10x

g'(x) =0, make y =0 to find find where g'(x) is 0

4x³-10x =0 , factor 2x

2x(2x²-5)= 0 , each factor must be 0

2x= 0, so x= 0

2x²-5 =0, so x = ±√5/2

we now have 3 critical points -√5/2, 0, and √5/2

make intervals (-∞, -√5/2), (-√5/2, 0) , (0, √5/2) and (√5/2, +∞)

pick a point to test on each interval: -2, -1, 1 and 2 for example, and

calculate g'(x) = 4x³-10x at those points

for x= -2 we have 4(-2)³-10(-2) = -12 , negative number, decrease

for x= -1 we have 4(-1)³-10(-1) =6, positive number, increase

for x= 1 we have 4(1)³-10(1) = -6, negative number, decrease

for x= 2 we have 4(2)³-10(2) = 12, positive number, increase

we went from a decrease to an increase on intervals (-∞, -√5/2), (-√5/2, 0) so x= - √5/2 ≈ -1.58 is a minimum

we went from a decrease to an increase on intervals (0, √5/2), (√5/2, +∞) so

x= √5/2 ≈ 1.58 is a minimum as well

4 0
3 years ago
How do you do this question?
r-ruslan [8.4K]

Step-by-step explanation:

y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1

dy/dx = 12√x

Arc length is:

s = ∫ ds

s = ∫₀¹ √(1 + (dy/dx)²) dx

s = ∫₀¹ √(1 + (12√x)²) dx

s = ∫₀¹ √(1 + 144x) dx

If u = 1 + 144x, then du = 144 dx.

s = 1/144 ∫ √u du

s = 1/144 (⅔ u^(³/₂))

s = 1/216 u^(³/₂)

Substitute back:

s = 1/216 (1 + 144x)^(³/₂)

Evaluate between x=0 and x=1.

s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]

s = 1/216 (145)^(³/₂) − 1/216

s = (145√145 − 1) / 216

5 0
3 years ago
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