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3 years ago

PLEASE HELP ME!!!!! I need Help Please With the 2nd question please any help me

Mathematics

1 answer:

galina1969 [7]3 years ago

3 0

Hello,
Please, see the attached file.
Thanks.

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-|-16| divided by(-8) multiplyed by25

Lynna [10]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The coordinates of the midpoint of GH are M(-2, 0), and the coordinates of one endpoint are H(4,-4).

Svetlanka [38]

The coordinate of point S from the giving coordinate point is (-8,4)

<h3>Midpoint of coordinates</h3>

The formula for calculating the midpoint of coordinate point is expressed as:

M(x,y) = {(x₁+x₂)/2, (y₁+y₂)/2}

Determine the measure of the coordinate S
-2 = 4+x₂/2

2(-2) = 4+x₂

x₂ = -4-4

x₂ = -8

Similarly

0 = -4+y₂/2

0(2) = -4+y₂

y₂ = 4

Hence the coordinate of point S from the giving coordinate point is (-8,4)

Learn more on midpoint here: brainly.com/question/5566419

#SPJ1

4 0

1 year ago

Please help soon! Thanks! Solve for x

spin [16.1K]

Answer:

$x=27\degree$

Step-by-step explanation:

$\because AC || DE.... (given)$

$\therefore m\angle CAD= m\angle EDF\\ (corresponding \: \angle s)$

$\therefore m\angle BAD= m\angle EDF\\(\because B\in \overleftrightarrow{AC})$

$\therefore m\angle BAD= 2x\\(\because m\angle EDF=2x)$

$In\:\triangle BAD,$

$m\angle BAD+m\angle BDA+m\angle ABD= 180\degree$

$2x+2x+72\degree = 180\degree$

$4x= 180\degree -72\degree$

$4x= 108\degree$

$x= \frac {108\degree}{4}$

$x=27\degree$

5 0

2 years ago

If the vegetable assembly line runs for 3 minutes, how many minutes would the fruit assembly line need to run to complete the or

Rudik [331]

Answer:

You need to say how many cans go by a minute to be able to answer this question.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di

Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, $\mu$ = 1.3 cm and Standard deviation, $\sigma$ = 0.01 cm

Also, since distribution is normal;

Z = $\frac{X -\mu}{\sigma}$ ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

P(X < 1.33) = P( $\frac{X -\mu}{\sigma}$ < $\frac{1.33 -1.3}{0.01}$ ) = P(Z < 3) = 0.99865

P(X <= 1.27) = P( $\frac{X -\mu}{\sigma}$ < $\frac{1.27 -1.3}{0.01}$ ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

= 0.00135

P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0

3 years ago