Answer: see below
<u>Step-by-step explanation:</u>
42) 11 < 3y + 2 < 20
<u> -2 </u> <u> -2 </u> <u> -2 </u>
9 < 3y < 18
<u> ÷3 </u> <u>÷3 </u> <u> ÷3 </u>
3 < y < 6
Graph: o----------o
3 6
44) 36 ≥ 1 - 5z > -21
<u> -1 </u> <u> -1 </u> <u> -1 </u>
35 ≥ -5z > -22
<u> ÷ -5 </u> ↓ <u> ÷ -5 </u> ↓ <u>÷ -5 </u>
7 ≤ z < 4.4
Graph: o------------ ·
4.4 7
46) 6b + 3 < 15 or 4b - 2 > 18
<u> -3 </u> <u> -3 </u> <u> +2 </u> <u>+2 </u>
6b < 12 4b > 20
<u> ÷6 </u> <u>÷6 </u> <u> ÷4 </u> <u>÷4 </u>
b < 2 or b > 5
Graph: ←--------o o---------→
2 5
48) 8d < -64 and 5d > 25
÷8 ÷8 ÷5 ÷5
d < -8 and d > 5
there is no number that is both less than - 8 and greater than 5
No Solution
Graph: (empty)
50) 15x > 30 and 18x < -36
<u> ÷15 </u> <u> ÷15 </u> <u>÷18 </u> <u>÷18 </u>
x > 2 and x < -2
there is no number that is both less than - 2 and greater than 2
No Solution
Graph: (empty)
I THINK there is a typo. Instead of "for problems each day", i think it's "four problems each day."
Anyway, we need to find how many days it takes Jeremy to complete the paper.
If he completes 8 problems on the first day and 4 on the rest of the days, after the first day he'll have 28 - 8 = 20 more problems.
And since he does 4 every day with 20 problems: 20 / 4 = 5 days.
Answer:
Im going to use the Pythagorean theorem.
a^2+b^2=c^2
Line AB is A, line CB is B, and line AC is C.
4^2+2^2=c^2
4^2=16 and 2^2=4
16+4=20^2=4.5
4.5 shoudl be your answer.
-Seth
1 is quotient , 2 is sum, 3 is difference , 4 is factor and product
Answer:
23 more cars than trucks.... It means you add 23 over the number of trucks
2 trucks | 2+23 =25
Do u get it
