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DIA [1.3K]
4 years ago
5

If you can get this I will give you 48 points.

Mathematics
1 answer:
Oliga [24]4 years ago
8 0
Quantity equation: t + s = 48kg
Copper equation: 23t + 79s = 44*48

Multiply the quantity equation by 23 to set the problem up for the elimination method. 

23t + 23s = 23*48
23t + 79s = 44*48

Subtract to solve for s. 

56s = 21*48
s = 18 [Number of 79% bars needed]
t = 48 - 18 = 30 [Number of 23% bars needed]
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What are the domain and range of f(x) = |x – 3 | + 6? Domain: {x | x is all real numbers} Range: {y | y ≥ 6} Domain: {x | x ≥ 3}
VARVARA [1.3K]

Answer:

Domain: {x | x is all real numbers} Range: {y | y ≥ 6}

Step-by-step explanation:

Domain is the set of all x values. No operations restrict the domain in this case. The domain is all real numbers.

Range is the set of all y values. Absolute value has a v shape starting at 0. Adding 6 raises this vertex to 6. The range is therefore all numbers greater than or equal to 6.

4 0
3 years ago
Read 2 more answers
Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat
yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

P(t) = 0.8t^{2} + 6t + 19000

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

P(t) = 0.8t^{2} + 6t + 19000

0.8t^{2} + 6t + 19000 = 34200

0.8t^{2} + 6t - 15200 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

0.8t^{2} + 6t - 15200 = 0

So a = 0.8, b = 6, c = -15200

Then

\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356

t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14

t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0
3 years ago
Two Questions please help and explain
ozzi
Question #2
Erica will have to work for 14 hours in order to buy her sneakers.
How to solve:
You subtract $31 from $150 which equals to $119
You multiply 8.50 (which is the amount of money she gets paid every hour) by the answers they gave you.
8.50 multiplied by 14 is 199
Erica had to work 14 hours to make $199

Your answer is D) 14
4 0
4 years ago
Read 2 more answers
What is (6 + 3e)4 - 5e and 3(x - 5) + 7(x + 2) ?
Dafna11 [192]

idk lol use photomath

6 0
3 years ago
Which number line represents the solution to the inequality x - 3 > 2
Ivahew [28]

Answer: x > 5

Step-by-step explanation: To solve for <em>x</em> in this inequality, our goal is the same as it would be if this were an equation, to get x by itself on one side.

Since 3 is being subtracted from x, we add 3 to

both sides of the inequality to get x > 5.

When graphing x > 5, we have an open circle on 5 and the

open circle tells us that 5 is not part of our answer.

Then we draw an arrow going to the right to represent

all possible solutions to this inequality, any number greater than 5.

6 0
3 years ago
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