Answer:
Step-by-step explanation:
This seems like a cross-multiplication problem.
![\frac{3}{20}=\frac{10}{x}\\ 3(x)=20(10)\\ 3x=200\\x= 200/3\\x=66.6](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B20%7D%3D%5Cfrac%7B10%7D%7Bx%7D%5C%5C%203%28x%29%3D20%2810%29%5C%5C%203x%3D200%5C%5Cx%3D%20200%2F3%5C%5Cx%3D66.6)
Answer; 66.6 mg/kg
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Answer: ![0 \le \theta < \frac{\pi}{4}](https://tex.z-dn.net/?f=0%20%5Cle%20%5Ctheta%20%3C%20%5Cfrac%7B%5Cpi%7D%7B4%7D)
</h3>
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How to get this answer:
Use the unit circle to note that
when
(aka 45 degrees)
Beyond this point, cosine is smaller than sine. This means that anything from 0 to pi/4 will have sine be smaller than cosine. It might help to graph y = sin(x) and y = cos(x) on the interval from x = 0 to x = pi.
The two curves y = sin(x) and y = cos(x) intersect at the point ![\left(\frac{\pi}{4}, \frac{\sqrt{2}}{2}\right)](https://tex.z-dn.net/?f=%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B4%7D%2C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%5Cright%29)
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Here's a more detailed picture of whats going on.
![\sin \theta < \cos \theta\\\\\sin \theta < \sqrt{1-\sin^2\theta}\\\\\sin^2 \theta < 1-\sin^2\theta \\\\2\sin^2 \theta < 1\\\\\sin^2 \theta < \frac{1}{2}\\\\\sin \theta < \sqrt{\frac{1}{2}}\\\\\sin \theta < \frac{1}{\sqrt{2}}\\\\\sin \theta < \frac{\sqrt{2}}{2}\\\\\theta < \arcsin\left(\frac{\sqrt{2}}{2}\right)\\\\\theta < \frac{\pi}{4}\\\\](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%20%3C%20%5Ccos%20%5Ctheta%5C%5C%5C%5C%5Csin%20%5Ctheta%20%3C%20%5Csqrt%7B1-%5Csin%5E2%5Ctheta%7D%5C%5C%5C%5C%5Csin%5E2%20%5Ctheta%20%3C%201-%5Csin%5E2%5Ctheta%20%5C%5C%5C%5C2%5Csin%5E2%20%5Ctheta%20%3C%201%5C%5C%5C%5C%5Csin%5E2%20%5Ctheta%20%3C%20%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Csin%20%5Ctheta%20%3C%20%5Csqrt%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5C%5Csin%20%5Ctheta%20%3C%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D%5C%5C%5C%5C%5Csin%20%5Ctheta%20%3C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%5C%5C%5C%5C%5Ctheta%20%3C%20%5Carcsin%5Cleft%28%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%5Cright%29%5C%5C%5C%5C%5Ctheta%20%3C%20%5Cfrac%7B%5Cpi%7D%7B4%7D%5C%5C%5C%5C)
Intersect the intervals
and
and you'll end up with the final answer ![0 \le \theta < \frac{\pi}{4}](https://tex.z-dn.net/?f=0%20%5Cle%20%5Ctheta%20%3C%20%5Cfrac%7B%5Cpi%7D%7B4%7D)
Answer:
three small smoothies require one and one-third bananas.
Step-by-step explanation:
Assuming that the three small smoothies are equal, and their sum equals the one large smoothie;
Number of bananas required for one large smoothie = three and three-third
three-thirds mean that out of three parts, three parts were selected. Therefore, three-thirds is the same thing as a whole or 1
∴ three and three-third ![= 3 + \frac{3}{3} = 3 + 1 = 4](https://tex.z-dn.net/?f=%3D%203%20%2B%20%5Cfrac%7B3%7D%7B3%7D%20%3D%203%20%2B%201%20%3D%204)
Therefore, the one large smoothie required 4 bananas.
Large smoothie = 4 bananas
three small smoothies ![= \frac{4}{3} = 1 \frac{1}{3}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B4%7D%7B3%7D%20%3D%201%20%5Cfrac%7B1%7D%7B3%7D)
Hence, three small smoothies require one and one-third bananas.
Answer:
1700
Step-by-step explanation:
the answer is on the other answer
mark pls