The probability that Rebecka selects a terrier and Aaron selects a retriever is 10/121
<h3>How to determine the probability?</h3>
The distribution of the puppies is given as:
4 poodles, 5 terriers, and 2 retrievers
The probability of selecting a terrier is;
P(terrier) = 5/11
The probability of selecting a retriever is;
P(retriever) = 2/11
The required probability is
P = 5/11 * 2/11
Evaluate
P = 10/121
Hence, the probability that Rebecka selects a terrier and Aaron selects a retriever is 10/121
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Answer:
the answer is 12.7, you add four plus 8.7
Answer:
Step-by-step explanation:
we have
Solve for m
That means-----> isolate the variable m
Factor the variable m in the equation
![g=m[4c-3]](https://tex.z-dn.net/?f=g%3Dm%5B4c-3%5D)
Divide by (4c-3) both sides
Rewrite
Number 2 is already a mixed number. But it says mixed number as a decimal. So -1 29/40 as a decimal is -1.725.
The equation for a equilateral triangle is the side squared times root 3 divided by 4
