vertical asymptote at x = 2 and x = - 2
horizontal asymptote at y = 2
the function → ± ∞ at x = 2 and x = - 2 ⇒ vertical asymptotes
As x → ± ∞, y → -2 ⇒ y = -2 is a horizontal asymptote
The answer will be 3/5
to find the slope you must use the formula
y1-y2/x1-x2.
A. Not a function since we have the points (-1,0) and (-1,3). The x value repeats while the y values are different. Plugging in x = -1 leads to multiple outputs, which shows we don't have a function. To get a better visual, you can plot the points. You'll see that the points form a vertical line. Therefore, this graph fails the vertical line test.
B. This is a function. All of the x values are different. The points, when graphed, pass the vertical line test. In other words, its impossible to draw a vertical line through any two points on the graph. Any x input here leads to exactly one y output.
C. This is not a function. Like choice A, we have repeated x values. In this case we have (4,6) and (4,7). The x value x = 4 repeats itself leading to multiple outputs y = 6 and y = 7
D. This is also not a function. The x value x = 0 repeats itself. The graph fails the vertical line test.
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Answer: Choice B
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<span>Exponential decay are; the domain is all real numbers, the base must be less than 1 and greater than 0 and the function has a constant multiplicative rate of change. The answers are letters A, D and E. An example is w</span>hen there are 70000 bacteria
present in a culture and reduced by half every four hours, the number of
bacteria will decrease. The bacteria will experience an exponential decay
because it decreases its number at a constant decay.
Answer:
Step-by-step explanation:
1 billion = 10^9
10^9 people * (10 Liters)/person = 10^10 Liters
