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Art [367]
3 years ago
7

Which is another way to write the expression t • (14 - 5)

Mathematics
2 answers:
zaharov [31]3 years ago
8 0
C is the answer by using distributive property

kaheart [24]3 years ago
7 0
T×(14-5)
=(t×14)-(t×5) is your final answer which is C. Hope it help!
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When adding two numbers, such as 123 and 423, care is taken to first line them up and then add like digits. How does expanding t
Ivanshal [37]
Since a polynomial is where we have like terms such as (1 x 10²) and (4 x 10²), we can add these up using the distributive property to get (5 x 10²) but still keep the 10². For example, it's similar to if we had 2x²+3x²=5x². The x² is still there, but we add up the 2 and 3. Similarly, we can add these up for 10^1 and 10^0
4 0
3 years ago
Ms. Williams wanted information about how well her students were
Arturiano [62]

Answer:

https://www.pittsfordschools.org/cms/lib/NY02205365/Centricity/Domain/683/ANSWER%20KEY%20TO%20ALL%20HOMEWORK.pdf

Step-by-step explanation:

If this doesn’t work I’m sorry but that’s the link!

5 0
3 years ago
Practice
Oxana [17]

Step-by-step explanation:

1. She tried 16 cups of fruit juice and 4 cups of ginger ale. That was too fruity.

Here the taste was too fruity, and the ratio used is 16:4, so in the next attempt, she needs to use less than 16 cups of fruit juice and or more than 4 cups of ginger ale.

Here the quotient between the cups of juice and ginger is: 16/4 = 4

2. She tried 10 cups of fruit juice and 8 cups of ginger ale. That was too gingery.

Now, the ratio is too gingery, so she needs to use more fruit juice and less ginger.

Here the quotient between the cups of juice and ginger is: 10/8 = 1.25

so at this point, we know that if the quotient is 1.25 or less the mixture is too gingery, and if it is 4 or more is too fruity, so the range we need to point is (1.25, 4)

3. She tried 10 cups of fruit juice and 1 cup of ginger ale. That was too fruity.

Now the ratio is 10:1, she only diminished the amount of ginger used, now she needs to increment the number of cups of ginger used, but she needs to be careful to not use more than 7. (because she already knows that the ratio 10:8 ends being too gingery).

Here the quotient between the cups of juice and ginger is: 10/1 = 10, the range of interest still is: (1.25, 4)

4. She tried 8 cups of fruit juice and 4 cups of ginger ale. That was a little too gingery.

now the ratio is 8:4, and the mix ends being a little gingery.

This means that she may need to use a little bit less ginger or a little bit more juice.

Here the quotient between the cups of juice and ginger is: 8/4 = 2

So now the range of interest is (2, 4)

5: Now, knowing that the ratio 8:4 was a little bit gingery, it is a good idea to use a cup lees of ginger and test the mixture. If the mixture is still a little bit gingery, you can add a cup of juice, in this case, the ratio will be 8:3

If when you remove the first cup of ginger, the mixture now is a little bit juicy, you can add again the cup of ginger and a cup of juice, making the ratio 9:4

4 0
3 years ago
Match the English word or phrase to its math equivalent.
nydimaria [60]
Sum is addition, less than is subtraction, equals is is, division is of and multiplication is per
5 0
3 years ago
For each function below, determine whether or not the function is injective and whether or not the function is surjective. (You
Harlamova29_29 [7]

Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y

(a) f:R----> + R given by f(x) = x2 (i guess you written x^{2})

The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and x^{2} is always a positive real number.

(b) f:N----> + N given by f(n) = n2  (i guess you written n^{2})

As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.

(c) f: Zx Z → Z given by f(n, k) = n +k:

here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.

3 0
3 years ago
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