Ask question

Ask question

All categories

3 years ago

8

Lee wants to cut this piece of canvas into two rectangles that are 3x2 and 3x5. He wants the sum of the two small rectangles to

be the same as the area of the large rectangle. Can he do this? explain

1 answer:

lord [1]3 years ago

8 0

Yes because 3×2= 6 , 3×5= 15, 15 + 6 = 21

You might be interested in

In an animal hospital, 10 units of a certain medicine were injected into a dog. After 50 minutes, only 5 units remained in the d

amid [387]

Answer:

h

Step-by-step explanation:

4 0

3 years ago

Consider the following function: f(x) = x² - 4

dmitriy555 [2]

im not answerin, you thought

4 0

2 years ago

Find the volume of a rectangular prism if the length is 3x2, the width is 2x, and the height is x2 + 3x + 5. Use the formula V =

AURORKA [14]

You are given the length of a rectangular prism of 3x^2, width of 2x and height of x^2 + 3x +5. You are required to find the volume of a rectangular prism. Using the equation V = l x w x h, we multiply the three dimensions.

V = l x w x h
V = (3x^2)(2x)( x^2 + 3x +5)
V = 2x (3x^4 + 9x^3 + 15x^2)
<u>V = 6x^5 + 18x^4 + 30x^3</u> <u> </u>
<u>The volume of the rectangular prism is 6x^5 + 18x^4 + 30x^3.</u>

3 0

3 years ago

3x(-2x)8(-2)=30 what value of x makes the equation true.<br><br> A. 24<br> B.26<br> C.5<br> D.6

Leokris [45]

Answer:

Step-by-step explanation:

5 0

3 years ago

HELP PLSS ANYONE? I'VE TO SUBMIT ASAP

Alenkinab [10]

x =14

Answer:

$m\angle ABC = 51°$

Step-by-step explanation:

11. By inscribed angle theorem:

$83°=\frac{1}{2} \times (9x+40)°\\\\83°\times 2 = (9x+40)°\\166°= (9x+40)°\\166 = 9x + 40\\166 - 40 = 9x\\126 = 9x\\\\x = \frac{126}{9}\\\\\huge \red {\boxed {x = 14}}$

12. Again by inscribed angle theorem:

$(5x+11)°=\frac{1}{2} \times (16x-26)°\\\\2\times (5x+11)°= (16x-26)°\\(10x+22)°= (16x-26)°\\10x + 22 = 16x - 26\\22+26 = 16x - 10x\\48= 6x\\\\x = \frac{48}{6}\\\\\huge \purple{\boxed {x = 8}}\\m\angle ABC = (5x+11)°\\m\angle ABC = (5\times 8+11)°\\m\angle ABC = (40+11)°\\\huge \orange{\boxed {m\angle ABC = 51°}} \\$

7 0

3 years ago