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Leviafan [203]
3 years ago
14

Simplify the following expression: (1 point) 2x − 2y + 5z − 2x − y + 3z

Mathematics
2 answers:
Olin [163]3 years ago
7 0

Answer:

-3y + 8z

Step-by-step explanation:

2x -2x = 0

-2y + -y = -3y

5z + 3z = 8z

-3y + 8z

Karo-lina-s [1.5K]3 years ago
4 0

Answer: -3y + 8z

Step-by-step explanation:

2x -2x = 0

-2y + - y= -3y

5z + 3z= 8z

-3y + 8z

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Take the numbers to their prime factorization. Write the final answer in exponential form. (SHOW YOUR WORK)
emmainna [20.7K]

1. 2² times 7¹

2. 2² times 3²

3. 29 is a prime number already

4. 2¹ times 5¹ times 7¹

5. 5¹ times 11¹

6. 3⁴

7. 2³ times 3¹ times 7¹

8. 3² times 11¹

9. 3¹ times 5²

10. 2⁶

4 0
3 years ago
Pls answer correctly thank you!
Aleks04 [339]
Top left
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8 0
3 years ago
Read 2 more answers
A hiker is hiking in a valley. The height of the valley is h(x,y)=4x2+y2 where x and y are the east-west and north-south distanc
Ainat [17]

Answer:

A. \frac{\partial{h}}{\partial{t}}=0

Step-by-step explanation:

A. The problems asked for 2 ways to solve it, expanding the equation with the substitution  x(t)=2 cos(t) and y(t)=4 sin(t) to differentiate it . The other way is by chain rule.

Expanding and differentiating:

We start by substituting x(t)=2 cos(t) and y(t)=4 sin(t) in h(x,y)=4x2+y2:

h(x,y)=4x^{2}+y^{2}= 4(2cos(t))^{2}+(4sin(t))^{2}\\h(x,y)=4(4cos^{2}(t))+(16sen^{2}(t))\\h(x,y)=16cos^{2}(t)+16sen^{2}(t)=16(sen^{2}(t)+cos^{2}(t))\\h(x,y)=16

So, in the path that the hiker chose:

\frac{\partial{h}}{\partial{t}}=0

Chain rule:

We start differentiating h(x,y) using chain rule as follows:

\frac{\partial{h}}{\partial{t}}= \frac{\partial{h}}{\partial{x}}\frac{\partial{x}}{\partial{t}}+\frac{\partial{h}}{\partial{y}}\frac{\partial{y}}{\partial{t}}

Now, it´s easy to find all these derivatives:

\frac{\partial{h}}{\partial{x}}=8x\\\frac{\partial{x}}{\partial{t}}=-2sin(t)\\\frac{\partial{h}}{\partial{y}}=2y\\\frac{\partial{y}}{\partial{t}}=4cos(t)

Now we replace them in the chain rule, with the replacement x=2cos(t) and y=4sin(t) in the x,y that are left and we operate everything:

\frac{\partial{h}}{\partial{t}}= 8x(-2sin(t))+2y(4cos(t)

\frac{\partial{h}}{\partial{t}}= 8(2cos(t))(-2sin(t))+2(4sin(t))(4cos(t)

\frac{\partial{h}}{\partial{t}}= -32cos(t)sin(t)+32sin(t)cos(t)

\frac{\partial{h}}{\partial{t}}= 0

This will be our answer

6 0
3 years ago
C. what assumptions are you making in solving parts​ (a) and​ (b)? select all that apply.
Alexxx [7]
D hope this helps with it 
6 0
3 years ago
What are the vertex and x-intercepts of the graph of the function below?
SIZIF [17.4K]

I think the answer is C

4 0
3 years ago
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