Answer:
angle E = angle X; DF = WY
see the explanation
Step-by-step explanation:
The options of the question are
(A) angle E = angle X; DF = XY
(B) angle D = angle Y; EF = XY
(C) angle E = angle X; DF = WY
(D) angle F = angle X; DE = WX
we know that
If two figures are congruent, then its corresponding sides and its corresponding angles are congruent
In this problem
Triangles DEF and WXY are congruent
so
Corresponding sides are named using pairs of letters in the same position on either side of the congruence statement
DE≅WX
EF≅XY
DF≅WY
Corresponding angles are named using a letter in the same position on either side of the congruence statement
∠D≅∠W
∠E≅∠X
∠F≅∠Y
therefore
angle E = angle X; DF = WY
C. The only reason why you didn’t have a problem is that I don’t have a lot to say because if I don’t have to say that I don’t know why I don’t have to say that I have a bad attitude
The domain is the set of all values a function will accept as inputs.
2d = (v0 + v)t
2d/t = v0 + v
v0 = 2d/t-v
Answer:
Step-by-step explanation:
<u>For old circular garden:</u>
take the radius as r.
then use the formula to find area of circle: πr² ......this is old garden area.
<u>For new enlarged garden:</u>
the radius is twice the old radius so, radius = 2 * r = 2r ......enlarged radius
now find area for this new garden: π(2r)² → 4πr²
In common fractions: (old garden)/(new garden)
: ( πr² ) / ( 4πr² )
: 1/4