The height of a 12-year-old boy increased by 17% last year and by 12% this year. What is the total increase in percentage terms?

Mathematics

1 answer:

murzikaleks [220]2 years ago

6 0

Answer:

1. 12(1.17h) = 1.3104h Which is a 31.04% increase

Step-by-step explanation:

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Use the elimination method to solve the following system of equations.

aliya0001 [1]

The answer
2x - y + z = -3 (1)
2x + 2y + 3z = 2 (2)
3x - 3y - z = -4 (3)

 (1) - (2) 3y +2z =5
3 .(1) - 2.(2) 3y+5z = -1

let 's solve
3y +2z =5
3y+5z = -1
z= - 2, and 3y =5+4=9, y=3, so 2x - 3 -2 = -3 implies x= 1

finally x=1, y=3 and z= -2
proof
2x - y + z = -3?? 2.1 - 3 -2 = -3 (true)

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2 years ago

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wariber [46]

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2 years ago

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Ellen purchased a dishwasher, which cost $315 before the 9.22% sales tax. She used the machine an average of 10 times per week f

Natasha2012 [34]

Given:
Cost of dishwasher : 315 before sales tax
sales tax : 9.22%

Total cost = 315 * 1.0922 = 344.043

Average of 10 uses per week for the next 6 years before replacing it.
There are 52 weeks in a year.

10 uses per week * 52 weeks per year * 6 years = 3120 average uses

cost for water = 0.09 ; cost for electricity = 0.13 ; total cost per use = 0.22

0.22 * 3120 = 686.40 cost of use

purchase cost = 344.043
cost of use = 686.40
lifetime cost 1,030.443

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2 years ago

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Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$