The frequency at which the filter will be resonant is 1. 59 × 10^6 Hz
<h3>How to determine the frequency</h3>
The resonant frequency of the series RLC circuit is given as;
Frequency = 1/2π√(LC)
It means that the current will peak at the resonant frequency for both inductor and capacitor.
Substitute the values
Frequency = 1/2 × 3. 142 √ (50 × 10^-3 × 2 × 10^ -6)
Frequency = 1/2 × 3. 142 × 1 × 10 ^-7
Frequency = 1/ 6. 284 × 10^-7
Frequency = 1. 59 × 10^6 Hz
Thus, the frequency at which the filter will be resonant is 1. 59 × 10^6 Hz
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Answer:
14
Step-by-step explanation:
The period is the x distance for one full cycle.
The 1st peak is at 1 and the second peak at 15
The period is 15 - 1 = 14
Answer:
1215
Step-by-step explanation:
K(E) = MV^2
Answer:
9
Step-by-step explanation:
2 tickets = $14
so
1 ticket = $7
$63 divided by $7 = 9
Hope this helped!
- profparis