What in times equals 60
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The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
To learn more about the factor visit:
Answer:
- sum: 3x² -4x -4
- product: (x -2)(3x +2)
Step-by-step explanation:
The areas of four regions are given. We can simply add them to find the sum. To express them as a product, we need to look at common factors.
<h3>Sum</h3>The total of the given area expressions is ...
3x² +2x -6x -4 = 3x² -4x -4 . . . . sum
<h3>Product</h3>Extending the table to show common factors of each row and column, we have ...
Since each cell of the table is the product of the corresponding common factors, we can write the area as the product ...
(x -2)(3x +2) . . . . product