A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.
Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b
-2 = (3/4)*(12) + b
You'll get b= -11
So the equation of the parallel line intersecting the point given is y= 3/4x -11.
I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.
(f+g) (n) = (–5n +1 ) + (- 6n +2) = –11n +3
(f+g) (n) = –11n +3
(f+g) (–2) = – 11 (–2) +3 = 22 +3 = 25
I hope I helped you^_^
Answer:
<h2>
y = 6x - 1</h2>
Step-by-step explanation:
(0, -1) ⇒ x₁ = 0, y₁ = -1
(1, 5) ⇒ x₂ = 1, y₂ = 5
So the slope:
The slope-intercept form of the equation of line is y = mx + b, where m is the slope and b is the y-intercept of the line.
(0, -1) ⇒ x₀ = 0, y₀ = -1 ⇒ b = -1
Therefore:
y = 6x - 1 ← the slope-intercept form of the equation
8 2/3 ooooooorrrrrrrr 8.6
Answer:
142
Step-by-step explanation:
opposite angle theorem
