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Tasya [4]
4 years ago
10

(9r2+3r+6)+(6r2+2r)

Mathematics
1 answer:
Sliva [168]4 years ago
5 0

The terms 9r^2 and 6r^2 are like terms. We add the numbers to the left of the "r^2" to get 9+6 = 15.

So 9r^2+6r^2 becomes 15r^2

The r^2 stays the same. We do not say something like r^2+r^2 = r^4. You might be thinking of r^2 * r^2 = r^(2+2) = r^4

When it comes to adding like terms, we keep the variables the same.

The other pair of like terms are 3r and 2r, so they add to 3r+2r = 5r

--------------------------------------------------------------------------------------------

Overall,

(9r^2+3r+6)+(6r^2+2r) = (9r^2+6r^2)+(3r+2r)+6

(9r^2+3r+6)+(6r^2+2r) = 15r^2+5r+6

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3 years ago
A line has slope −5/3. Through which two points could this line pass?
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I hope this help you

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If 3/x = 5/y , what is the value of y/x?<br><br><br> (15 POINTS AND FREE BRAINIEST ANSWER!!)
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8 0
3 years ago
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PLEASE PLEASE PLEASE HELP ME
lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0
3 years ago
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Answer:

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4 0
3 years ago
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