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Vitek1552 [10]
3 years ago
11

20 POINTS HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
adell [148]3 years ago
8 0
I’m pretty sure it has 5 faces and maybe 7 edges and 6 vertices
IgorC [24]3 years ago
7 0
6 edges 5 faces 8 vertusis i think hope this helps
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Sin2x-sin2xcos2x=sin4x
yaroslaw [1]

It looks like the given equation is

sin(2x) - sin(2x) cos(2x) = sin(4x)

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

which lets us rewrite the equation as

sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)

Move everything over to one side and factorize:

sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0

sin(2x) - 3 sin(2x) cos(2x) = 0

sin(2x) (1 - 3 cos(2x)) = 0

Then we have two families of solutions,

sin(2x) = 0   or   1 - 3 cos(2x) = 0

sin(2x) = 0   or   cos(2x) = 1/3

[2x = arcsin(0) + 2nπ   or   2x = π - arcsin(0) + 2nπ]

… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

(where n is any integer)

[2x = 2nπ   or   2x = π + 2nπ]

… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

[x = nπ   or   x = π/2 + nπ]

… … …   or   [x = 1/2 arccos(1/3) + nπ   or   x = -1/2 arccos(1/3) + nπ]

7 0
3 years ago
What is the value of y in the equation 2 + y = −3?
Ket [755]
I’ve done these questions before and i’ve gotten confused because I have trouble with nagative numbers but i’ve gotten better st it. It’s -5
8 0
4 years ago
Read 2 more answers
) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= \dfrac{1}{2}

The length of bits : n = 10

Let X = Number of getting ones.

Then , X \sim Bin(n=10,\ p=\dfrac{1}{2})

Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}

=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})

=(\dfrac{1}{2})^{10}(210+252)

=(0.0009765625)(462)

=0.451171875\approx0.4512

Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0
4 years ago
2/3y + k = j. Solve for y
iVinArrow [24]

The value of y from the expression is y = 3/2(j-k)

<h3>Subject of formula</h3>

Given the expression below

2/3y + k = j.

Subtract k from both sides

2/3y = j - k

Divide both sides by 2/3

(2/3y)/2/3 =  (j-k)/(2/3)

y = 3/2(j-k)

Hence the value of y from the expression is y = 3/2(j-k)

Learn more on subject of formula here; brainly.com/question/657646

#SPJ1

7 0
2 years ago
Suppose 1 Bamboo Skewer Is About 30 Cm Long. How Many Skewers Would It Take To Make A Line 1 Million Centimeters Long?
Soloha48 [4]

(1,000,000 centimeters) x (1 skewer/30centimeters) =

                  1,000,000 /30 skewers =  33,333 whole skewers,
                                                           plus one piece of one more skewer
                                                           cut into 3 equal pieces with the other
                                                           two pieces discarded.    

                 Another way to look at it:   <em>33,334 skewers</em>,
                                                            with 2/3 of one of them not included.                          

8 0
3 years ago
Read 2 more answers
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