Determine is the solution set for the system of equations shown is the empty set contains one point or is infinite X+2y=0; 2x+4y
=0
1 answer:
We can use elimination to solve the system:
x+2y=0 Multiply the first equation by negative 2 so we can eliminate
2x+4y=0
-2-4y=0 Add them, -2X+2X= 0, -4Y+4Y= 0
2x+4y=0
0=0
Since 0 is indeed equal to 0 you have INFINITELY MANY SOLUTIONS.
you could also put both equation in slope intercept form and see if the slopes and Y-intercept are the same.
You might be interested in
Answer:
the initial value is 2
Step-by-step explanation:
"y=mx+b" is the equation
"b" is the initial value, and there is no "b" value
Answer:
-0.1846
Step-by-step explanation:
-5/13 + 1/5 = -0.1846
Answer: A B and C
Step-by-step explanation:
I did the usatestprep
Step-by-step explanation:
= √2x × √8x³
= √(2.8x^4)
= √16x^4
= 4x²
The three numbers are 23, 161, and 123.