<span>Vertical farming is the exercise of creating foodstuff and medication in sheer laden layers, vertically inclined exteriors and/or combined in other structures. The modern thoughts of vertical farming use indoor farming methods and controlled-environment agriculture (CEA) technology, where all environmental issues can be well-ordered. So knowing all of this, the negative outcome would be D.</span>
Explanation:
An application interface or user interface ,is the set of features an application provides so that user may supply input to and recieve output from,the program.
Answer:
It is The National Institute for Automotive Service Excellence.
Explanation:
The suspense and reaction time of the car . So for example if a car pulled out suddenly and was about to hit you, you could make the car so it functionally knows how to react
Answer:
Option d) B is 1.33 times faster than A
Given:
Clock time, 

No. of cycles per instructions, 

Solution:
Let I be the no. of instructions for the program.
CPU clock cycle,
= 2.0 I
CPU clock cycle,
= 1.0 I
Now,
CPU time for each can be calculated as:
CPU time, T = 


Thus B is faster than A
Now,


Performance of B is 1.33 times that of A