Question

How do I do this? Please explain it. Thank you.

Answer 1

Answer:

slope = - $\frac{14}{3}$

Step-by-step explanation:

the slope of the secant line in the closed interval [a, b ] is

slope = $\frac{f(b)-f(a)}{b-a}$

here [a, b ] = [1, 4 ]

f(b) = f(4) = - $2^{4}$ + 5 = - 16 + 5 = - 11

f(a) = f(1) = - $2^{1}$ + 5 = - 2 + 5 = 3

slope = $\frac{-11-3}{4-1}$ = $\frac{-14}{3}$ = - $\frac{14}{3}$