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Anna [14]
3 years ago
5

The width of a rectangular painting is 3 in. less than the length. The area of the painting is 40 in ^2 .Find the length and wid

th.
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
6 0

Answer:

Mark me as brainlist

Step-by-step explanation:

a) (h + 5)(2h + 8) is the expression for the combined area of the painting and frame

b) The combined area when h = 12 is 544 square inches

c) The combined area when h = 15 is 760 square inches

Solution:

Given that,

A frame that is 2.5 inches wide goes around the painting

The frame will go around all 4 sides of the painting.

That means that the length of each side of the painting will increase by 2.5 inches

Therefore,

The height of painting and frame is:

h = h + 2.5 + 2.5

h = h + 5

(2.5  inches on the top and the bottom)

Also given that,

Width of a rectangular painting is 3 inches more than twice the height

w = 3 + 2h

Now the width of painting and frame is:

w = 3 + 2h + 2.5 + 2.5

(Again, 2.5 inches on the top and the bottom)

w = 2h + 8

Thus the combined area of the painting and frame is:

B) Substitute h = 12 inches

Thus the combined area when h = 12 is 544 square inches

C) Substitute h = 15 inches

Thus combined area when h = 15 is 760 square inches

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3 years ago
The value of a book is $150 and decreases at a rate of 4% per year. Find the value of the book after 12 years
nevsk [136]
If it decreases at 4% every year, then its value becomes:

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At the end of the 3 years its value becomes:  150*(0.96)*(0.96)*(0.96) = 150(0.96)³

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<span>≈ 91.91

Value at the end of 12 years becomes ≈ $</span><span>91.91

I hope this helps.
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FromTheMoon [43]

Answer : ∠map = 7\times17-13=119-13=106\textdegree

∠mac = 3\times17+13=51+13=64\textdegree

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Since we have given that

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