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Ann [662]
3 years ago
7

Consider triangle ABC. The legs have a length of 5 units each. What is the length of the hypotenuse of the triangle?

Mathematics
2 answers:
Korvikt [17]3 years ago
6 0

Answer:

5\sqrt{2} units.

Step-by-step explanation:

We have been given that two legs of triangle ABC measures 5 units each. We are asked to find the length of the hypotenuse.

We will use Pythagoras theorem to solve for the hypotenuse of triangle ABC.

\text{Hypotenuse}^2=\text{Leg}^2+\text{Leg}^2

Substituting our given values in above equation we will get,

\text{Hypotenuse}^2=5^2+5^2

\text{Hypotenuse}^2=25+25

\text{Hypotenuse}^2=50

Upon taking square root of both sides of our equation we will get,

\text{Hypotenuse}=\sqrt{50}

\text{Hypotenuse}=\sqrt{25*2}

\text{Hypotenuse}=5\sqrt{2}

Therefore, the length of hypotenuse of triangle ABC is 5\sqrt{2} units.

kolezko [41]3 years ago
3 0

Here's what you were looking for.

Ur welcome :)


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