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valentina_108 [34]
2 years ago
6

Hello, please answer the question, please show work

Mathematics
1 answer:
kvasek [131]2 years ago
8 0
14 1/4
you just multiply the two
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2.3 repeating as a fraction​
Marat540 [252]
23/10 = 2 and 3/10




I hope this helped
7 0
3 years ago
Read 2 more answers
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
kompoz [17]

Answer:

K(-4,8) is the ortho center.

Step-by-step explanation:

In a right angled triangle, The vertex of the right angle is the ortho center.

Here we are given

J(-4,-1), K(-4,8) & L(2,8)

Using distance formula we get

JK^{2}= (-4+4)^{2}+ (8+1)^{2}=0+81=81

KL^{2}= (-4-2)^{2}+ (8+-8)^{2}=36+0=36

JL^{2}= (-4-2)^{2}+ (8+1)^{2}=36+81=117

So we can say that

JK^2 + KL^2=JL^2

By converse of pythagorean theorem we get

Hence the Vertex of the right angle is K(-4,8)

K(-4,8) is the ortho center.

7 0
3 years ago
Solve the question below.<br><br><br> 15<br><br> 17<br><br> 14<br><br> 16
Nadusha1986 [10]
To get the distance DC we proceed as follows:
AB-CD
=11-3
=8 
BC=15
hence using Pythagorean theorem
c²=a²+b²
c=DC
a=BC
b=8
thus
c²=15²+8²
c²=225+64
c²=289
thus
c=√289
c=17 units

Answer: B. 17 units
8 0
3 years ago
Expand and simplify pla
k0ka [10]
Y = f(3f - 4g + 3) +7g(3f - 4g + 3)
= 3f^2 - 4fg + 3f + 21fg - 28g^2 + 21g
= 3f^2 + 3f + 17fg + 21g - 28g^2
4 0
2 years ago
A computed measure of how much scores vary around the mean score
Paladinen [302]
That's called <span>standard deviation.

Hope this helps !

Photon</span>
5 0
2 years ago
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