Given:
![f(x)=\sqrt[]{5x^2-2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B%5D%7B5x%5E2-2%7D)
f(X) will be differentiated by chain rule.
![\begin{gathered} f^{\prime}(x)=\frac{1}{2\sqrt[]{5x^2-2}}\lbrack5(2x)\rbrack \\ f^{\prime}(x)=\frac{5x}{\sqrt[]{5x^2-2}} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f%5E%7B%5Cprime%7D%28x%29%3D%5Cfrac%7B1%7D%7B2%5Csqrt%5B%5D%7B5x%5E2-2%7D%7D%5Clbrack5%282x%29%5Crbrack%20%5C%5C%20f%5E%7B%5Cprime%7D%28x%29%3D%5Cfrac%7B5x%7D%7B%5Csqrt%5B%5D%7B5x%5E2-2%7D%7D%20%5Cend%7Bgathered%7D)
Answer:
There are two ways to do this problem algebraically or trigonometrically.
Algebraically/geometrically
The ratios of the sides of a 30/60/90 tri. are x, x√3, 2x (short leg, long leg, hyp). Therefore, if the long leg is 6 'units'. then 6 = x√3. x = 6√3.
The hyp is 2x then the hypotenuse is 2(6√3) = 12√3, rationalizing is 12√3/3 = 4√3
Using Trig.
We can use sinx = y/r = opp/hyp. The long leg of 6 is opposite 60 degrees (pi/3).
Therefore, sin(pi/3) = 6/r =
r = 6/sin(pi/3) = 6/(√3/2) = 12/√3, when you rationalize you get 12√3/3 = 4√3
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Answer:
length of a rectangle is 5 more than twice the length. I believe
you mean the length of a rectangle is 5 more than twice the
width.
From the information given we can make two equations,
thus forming a system to solve. We know the perimeter
of a rectangle is 2(length + width) and area = length*width.
length of a rectangle is 5 more then twice the width:
L = 2w + 5
The perimeter is 130:
2(L+w) = 130
L+w = 65
Since we know L=2w+5 we can substitute that into 2nd equation
to solve for w
2w + 5 + w = 65
3w = 60
w = 20
L = 2w+5 = 45
The area is length*width = 20(45) = 900 square units
