How do you solve this problem?
1 answer:
Easy, it says "for ANY positive integer" so just test any positive integer
remember that n! means times all integers from 1 to that number n
lets try 1
(1+1)!/(1!)-1=
(2!)/(1!)-1=
2/1-1=
2-1=
1
if you don't believe me, try 2
(2+1)!/(2!)-2=
(3!)/(2!)-2=
(6)/(2)-2=
3-2=
1
te answer is 1, B
and number 9
easy, remember the exponential law
(x^m)(x^n)=x^(m+n)
jsut add the exponents
first gropu like bases
(r^2r^2/3)(t^1/2t^-3/2)
add bases
(r^2 and 2/3)(t^-1)=
(r^2∛(r^2))(1/t)=
![\frac{r^{2} \sqrt[3]{r^{2}} }{t}](https://tex.z-dn.net/?f=%20%5Cfrac%7Br%5E%7B2%7D%20%5Csqrt%5B3%5D%7Br%5E%7B2%7D%7D%20%7D%7Bt%7D%20)
remember that n! means times all integers from 1 to that number n
lets try 1
(1+1)!/(1!)-1=
(2!)/(1!)-1=
2/1-1=
2-1=
1
if you don't believe me, try 2
(2+1)!/(2!)-2=
(3!)/(2!)-2=
(6)/(2)-2=
3-2=
1
te answer is 1, B
and number 9
easy, remember the exponential law
(x^m)(x^n)=x^(m+n)
jsut add the exponents
first gropu like bases
(r^2r^2/3)(t^1/2t^-3/2)
add bases
(r^2 and 2/3)(t^-1)=
(r^2∛(r^2))(1/t)=
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Answer:
We have to travel 26.93 units from platform B to C.
Step-by-step explanation:
Length of a segment having coordinates and
is determined by the formula,
From the graph attached,
Coordinates of the points B and C are (-25, -20) and (-15, 5) respectively.
Distance between these points B and C Or length of BC will be,
BC =
=
=
=
= 26.93 units
Therefore, we have to travel 26.93 units from platform B to C.
Answer:
The inequality can be represented as:
Solution for the inequality:
Step-by-step explanation:
Given :
The quotient of a number and 4 is at most 5.
To write an inequality for the given statement.
Solution:
The quotient of two variables and
can be represented as :
Thus the quotient of the number and 4 can be represented as:
⇒
The quotient is at most 5 which means it is less than or equal to 5.
Therefore, the inequality can be represented as:
<em>Solving for</em> .
Multiplying both sides with 4.
Thus, the number must be at most 20.