Solve for xsin3⁡x+cos3⁡x=1" role="presentation" style="margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; font-family: inherit; font-size: 15px; vertical-align: baseline; box-sizing: inherit; display: inline; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">xsin3x+cos3x=1xsin3⁡x+cos3⁡x=1

sin3⁡x+cos3⁡x=1(sin⁡x+cos⁡x)(sin2⁡x−sin⁡x⋅cos⁡x+cos2⁡x)=1(sin⁡x+cos⁡x)(1−sin⁡x⋅cos⁡x)=1" role="presentation" style="margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; font-family: inherit; font-size: 15px; vertical-align: baseline; box-sizing: inherit; display: inline; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">sin3x+cos3x=1(sinx+cosx)(sin2x−sinx⋅cosx+cos2x)=1(sinx+cosx)(1−sinx⋅cosx)=1

6 0

2 years ago

The graph of f(x) is obtained by reflecting the graph of g(x)=3|x| over the x-axis.

Alinara [238K]

Answer:

Choice B), $f(x) = -3|x|$ .

Step-by-step explanation:

Each point on the graph of $g(x)$ can be represented as $(x, g(x))$ .

When the graph of $g(x)$ is reflected over the x-axis, each point on the graph is also reflected over the x-axis. The x-coordinate of each point will not change but the sign in front of the y-coordinate will flip. For example, $1$ (same as $+1$ ) will become $-1$ , and vice versa. In general, $(x, g(x))$ will become $(x, -g(x))$ .

On the other hand, points on the graph of $f(x)$ can be represented as $(x, f(x))$ . $f(x)$ is the reflection of $g(x)$ , so $(x, -g(x))$ and $(x, f(x))$ shall be equivalent. In other words,

$f(x) = -g(x) = - 3|x|$ .

5 0

3 years ago