what you do is for y=ax^2+bx+c 1. isolate x terms y=(ax^2+bx)+c undistribute a y=a(x^2+(b/a)x)+c complete the square by take 1/2 of b/a and squaring it then adding negative and postive inside y=a(x^2+(b/a)x+(b^2)/(4a^2)-(b^2)/(4a^2))+c complete square too messy \ anyway
y=2x^2+24x+85 isolate y=(2x^2+24x)+85 undistribute y=2(x^2+12x)+85 1/2 of 12 is 6, 6^2=36 add neagtive and postivie isnde y=2(x^2+12x+36-36)+85 complete perfect square y=2((x+6)^2-36)+85 distribute y=2(x+6)^2-72+85 y=2(x+6)^2+13
obviously he needs to keep 40 bucks in his bank and he just bought like $145 yeezys so.. i dont know how to explain but uh lets just add 40 bucks to 145 which is 185.