Let us take 'a' in the place of 'y' so the equation becomes
(y+x) (ax+b)
Step-by-step explanation:
<u>Step 1:</u>
(a + x) (ax + b)
<u>Step 2: Proof</u>
Checking polynomial identity.
(ax+b )(x+a) = FOIL
(ax+b)(x+a)
ax^2+a^2x is the First Term in the FOIL
ax^2 + a^2x + bx + ab
(ax+b)(x+a)+bx+ab is the Second Term in the FOIL
 Add both expressions together from First and Second Term  
= ax^2 + a^2x + bx + ab
<u>Step 3: Proof
</u>
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
Identity is Found
.
Trying with numbers now
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)
((10)+8)(7) =(2*25)+(4*5)+(40)+(16)
(18)(7) =(50)+(20)+(56)
126 =126
 
        
             
        
        
        
Answer is C. By solving x-y=-5 to x=-5+y and converting 2x + y = -1 into 2x + x + 5 = -1 the answer becomes -2 =x. By plugging that into 2 (-2) + y = -1, the answer is y=3. So your answer is C
        
             
        
        
        
Answer:
domain= {x/x€R/x≠0}
Step-by-step explanation:
 
        
             
        
        
        
Answer:
 x^2 - 14x + 49.
Step-by-step explanation:
 (x − 7)^2
= (x - 7)(x - 7)
= x(x - 7) - 7(x - 7)
= x^2 - 7x - 7x + 49
= x^2 - 14x + 49.