what you do is for y=ax^2+bx+c 1. isolate x terms y=(ax^2+bx)+c undistribute a y=a(x^2+(b/a)x)+c complete the square by take 1/2 of b/a and squaring it then adding negative and postive inside y=a(x^2+(b/a)x+(b^2)/(4a^2)-(b^2)/(4a^2))+c complete square too messy \ anyway
y=2x^2+24x+85 isolate y=(2x^2+24x)+85 undistribute y=2(x^2+12x)+85 1/2 of 12 is 6, 6^2=36 add neagtive and postivie isnde y=2(x^2+12x+36-36)+85 complete perfect square y=2((x+6)^2-36)+85 distribute y=2(x+6)^2-72+85 y=2(x+6)^2+13
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.