We can say that lines A and D are <em>perpendicular</em>.
The next day high temperature will be -18.7
The temperature will be considered as 'warmer' as the temperature increased and will be considered as 'colder' if the temperature decreased.
So, if the temperature for the next day is 5 degrees warmer, then it must be:
-23.7 + 5 = -18.7 Degree
See the file attached (photo) above - That is the graph for (-(8*x))+15
Graph the line using the slope and y-intercept, or two points.
Slope: −8
y-intercept: (0,15)
x y
0 15
1 7
#CarryOnLearning
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<em><u>→</u></em><em><u>X</u></em><em><u>x</u></em><em><u>K</u></em><em><u>i</u></em><em><u>m</u></em><em><u>0</u></em><em><u>2</u></em><em><u>x</u></em><em><u>X</u></em></h3>
We will need to find the area of the circle. We will use this formula:
A =

* radius^2
The question says we will use 3.14 for

.
And we know radius is equal to 22.
A = 3.14 * 22^2
A = 3.14 * 484
A = 1519.76
Round to the nearest tenth.
A = 1519.8
So, the maximum area the sprinkler can water is <span>1519.8</span> ft squared.
EDIT:
I found a mistake in my answer.
Hello,
With
y=x²-4x-21
y=-5x-22
==>x²-4x-21=-5x-22
==>x²+x+1=0
In R, no solution for Δ=1-4=-3<0