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Vsevolod [243]
2 years ago
6

What is the recursive rule for this geometric sequence? 7, 21, 63, 189,…

Mathematics
1 answer:
Marysya12 [62]2 years ago
4 0

Answer:

The top choice is the answer. a1=7; an= 3*a_(n-1)

Step-by-step explanation:

Begin by finding out what the terms are multiplied by. It is a geometric sequence so multiplication is involved.

Take the 3rd term (63) and divide it by the second term.

63/21 = 3

What this means is that each term in the sequence is multiplied by 3 to get to the next term.

The first term is 7

So the answer is an = 3* a_n-1

The answer must be the top one. See if it works.

a2 = 3*a_(2 -1 )

a2 = 3 * a1

a2 = 3 * 7

a2 = 21 which it does.

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[-5, 4) ∪ (4, ∞)

Step-by-step explanation:

Given functions:

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\begin{aligned}(f\:o\:g)(x)&=f[g(x)]\\ & =\dfrac{1}{\sqrt{x+5}-3} \end{aligned}

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3 0
2 years ago
the taxi charges a flat fee of $3.75, plus $1.50 per kilometer driven. What is the total cost of a 10 km trip?
Lubov Fominskaja [6]

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Solve the equation on the interval [0,2π). 7 sec x-7=0, x=?
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\huge \bf༆ Answer ༄

Let's solve ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \sec(x)  - 7 = 0

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{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sec(x)  = 7 \div 7

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sec(x)  = 1

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 0

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