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Vsevolod [243]
3 years ago
6

What is the recursive rule for this geometric sequence? 7, 21, 63, 189,…

Mathematics
1 answer:
Marysya12 [62]3 years ago
4 0

Answer:

The top choice is the answer. a1=7; an= 3*a_(n-1)

Step-by-step explanation:

Begin by finding out what the terms are multiplied by. It is a geometric sequence so multiplication is involved.

Take the 3rd term (63) and divide it by the second term.

63/21 = 3

What this means is that each term in the sequence is multiplied by 3 to get to the next term.

The first term is 7

So the answer is an = 3* a_n-1

The answer must be the top one. See if it works.

a2 = 3*a_(2 -1 )

a2 = 3 * a1

a2 = 3 * 7

a2 = 21 which it does.

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Answer:

C and D are the same answers but one of those.

Step-by-step explanation:

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What is the distance between B to A<br> Please add the method.<br> The angle is 61 (a bit blurry)
deff fn [24]

Answer:

24.03 units (nearest hundredth)

Step-by-step explanation:

The distance between B and A is:  AB = AH + HB

We have been given AH, so we just need to find the measure of HB.

First, find the angle AOH using tan trig ratio:

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:

  • \theta = ∠AOH
  • O = AH = 8
  • A = OH = 19.80

\implies \sf \tan(\angle AOH)=\dfrac{8}{19.8}

\implies \sf \angle AOH = 22.00069835^{\circ}

   ∠BOA = ∠BOH + ∠AOH

⇒ ∠BOH = ∠BOA - ∠AOH

⇒ ∠BOH = 61° - 22.00069835°

               = 38.99930165°

Now we can find HB by again using the tan trig ratio:

Given:

  • \theta = ∠BOH = 38.99930165°
  • O = HB
  • A = OH = 19.80

Substituting given values:

\implies \sf \tan(38.99930165^{\circ})=\dfrac{HB}{19.80}

\implies \sf HB=19.80 \tan(38.99930165^{\circ})

\implies \sf HB=16.03332427

Therefore:

   AB = AH + BH

⇒ AB = 8 + 16.03332427

         = 24.03 units (nearest hundredth)

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