A six sided cube is rolled. find the probability of P (4) as a decimal

Soup ordinarily priced at 2 cans for .33 cents may be purchased in lots of one dozen for 1.74, what is the savings per a can whe

Sidana [21]

Answer:

Savings per can would be 0.02 cents when purchased in lots.

Step-by-step explanation:

Given:

Ordinary price of soup 2 cans = 0.33 cents.

When purchases in lots 12 cans = 1.74

We need to find the saving per can when purchased in Lots.

Solution:

Ordinary price of soup 2 cans = 0.33 cents.

1 can = Cost of 1 can when purchased ordinary.

By Using Unitary method we get;

Cost of 1 can when purchased ordinary = $\frac{0.33}{2} = 0.165\ cents/can$

Now we will find the Cost of 1 can when purchased in lot.

12 cans = 1.74

1 can = Cost of 1 can when purchase in lot.

Again by using Unitary method we get;

Cost of 1 can when purchase in lot = $\frac{1.74}{12} = 0.145\ cents/can$

Savings = Cost of 1 can when purchase in lot - Cost of 1 can when purchased ordinary

Savings = $0.165-0.145=0.02\ cents/can$

Hence Savings per can would be 0.02 cents when purchased in lots.

5 0

2 years ago

In a class of 24 stundents 13 students sold over 150 raffle tickets each and the rest of the class sold about 60 raffle tickets

Lisa [10]

Yes, 13•150=1950 and then 11•60=660 so combined they equal 2610

4 0

3 years ago

2. P337. 23. A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is 10 mm, and

Rashid [163]

Answer:

B is True

A, C. D are false

Step-by-step explanation:

Given :

Sample size, n = 120

Mean diameter, m = 10

Standard deviation, s = 0.24

Confidence level, Zcritical ; Z0.05/2 = Z0.025 = 1.96

The confidence interval represents how the true mean value compares to a set of values around the mean computed from a set of sample drawn from the population.

The population here is N = 10000

To obtain

Confidence interval (C. I) :

Mean ± margin of error

Margin of Error = Zcritical * s/sqrt(n)

Margin of Error = 1.96 * 0.24/sqrt(120)

Confidence interval for the 10,000 ball bearing :

10 ± 1.96 * (0.24) / sqrt(120)

Hence. The confidence interval defined as :

10 ± 1.96 * (0.24) / sqrt(120) is the 95% confidence interval for the mean diameter of the 10,000 bearings in the box.

4 0

2 years ago

2. Starting at a fixed time, each car entering an intersection is observed to see whether it turns left (L), right (R), or goes

jasenka [17]

Answer:

Natural numbers (integers greater than zero)

X = 3, 5, 4, 4, 3

Step-by-step explanation:

The least number of cars that can be observed in this experiment is 1, if the first car turns left. On the other hand, the experiment could go on forever if no car ever turns left, thus the highest number of cars approaches infinite.

The possible values of X are integers greater than zero, which are known as the Natural numbers.

If X = number of cars observed, simply count the number of letters in each outcome for the value of X:

Outcome = RRL, AARRL, AARL, RRAL, ARL

X = 3, 5, 4, 4, 3

7 0

3 years ago

Tell how you can use tools to solve a math <br> problem

castortr0y [4]

By measuring and knowing the wait of the ounces and height

5 0

3 years ago