I believe the mass of the product will be 400 grams. This is because according to the law of conservation of mass, mass is neither created nor destroyed . In a closed system, the mass of reactants is equal to mass of products. Therefore, since the total mass of the reactants is 400 grams then the mass of the products will still be 400 grams
OR
200
1.=b)
2.=b)
3.=a)
4.=a)
5.=d)
6.=a)
7=d)
Answer:
The measured absorbance will be too large.
Explanation:
Fe³⁺(aq) + SCN⁻(aq) ⟶Fe(SCN)²⁺(aq)
A = log₁₀(I₀/I)
If the student orients the cuvette so that the path of the light is through the frosted sides of the cuvette, little light will be able to reach the detector.
The measured intensity (I) will be quite small, so the absorbance (A) will be unusually large.
Answer:
Okay, we first need to calculate the amount of heat energy required to raise the temperature of water to its boiling point(100°C) using the formula Q= mcθ where Q is the amount of heat energy required, m is the mass of the sample of water, c is the specific heat capacity of water and θ is the change in temperature.
Q= (20.0)(0.999043976)(100-25)
= 1.498565965x10³ cal
We now need to calculate the amount of heat energy required to convert the sample of water to steam at its boiling point using the formula Q= mL where Q is the amount of heat energy required, m is the mass of the sample of water and L is the latent heat of vapourisation of water.
Q= (20.0)(540)
= 1.08x10⁴ cal
Now, we shall calculate the amount of heat energy required to raise the temperature of the steam to 150°C using the formula Q= mcθ.
Q= (20.0)(0.485)(150-100)
= 485 cal
Finally, we add up the amount of heat energy required at each of the three stages to determine the net amount of heat energy required, Qₙ.
Qₙ= (1.498565965x10³)+(1.08x10⁴)+(485)
= 1.278356597x10⁴ cal
= 1.28x10⁴ cal correct to 3 significant figures.
The Answer you are looking for is true