<u>Answer:</u> The concentration of 
in three significant figures will be 0.899 mol/L.
<u>Explanation:</u>
For the given reaction:
The above reaction follows zero order kinetics. The rate law equation for zero order follows:
![k=\frac{1}{t}([A_o]-[A])](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%28%5BA_o%5D-%5BA%5D%29)
where,
k = rate constant for the reaction = 
t = time taken = 10 sec
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial concentration of the reactant = 0.962 mol/L
[A] = concentration of reactant after some time = ?
Putting values in above equation, we get:
![6.28\times 10^{-3}=\frac{1}{10}(0.962-[A])](https://tex.z-dn.net/?f=6.28%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7B1%7D%7B10%7D%280.962-%5BA%5D%29)
![[A]=0.899mol/L](https://tex.z-dn.net/?f=%5BA%5D%3D0.899mol%2FL)
Hence, the concentration of in three significant figures will be 0.899 mol/L.
The answer to that question would be C
The answer is: The reactants were not heated long enough.
For all chemical reaction some energy is required and that energy is called activation energy (energy that needs to be absorbed for a chemical reaction to start).
Activation energy is the minimum energy colliding particles must have in order to react.
By lowering activation energy, reaction need less heat.
In this example, there is not enough heat.
<span>We are converting a compound know as Aluminum Bromide to grams. the base unit of the substance is the mole. So albr3 would equal to 266.693538 grams</span>
