Answer:
The vapor pressure of the solution is 3.69 torr
Explanation:
Step 1: Data given
Mole fraction of benzene in the solution = 0.139
P° of benzene is 26.5 torr
Step 2: Calculate the vapor pressure of the solution
Psolution = Xbenzene * P°benzene
⇒with Psolution = the vapor pressure of the solution
⇒with Xbenzene = the mole fraction of benzene = 0.139
⇒with P°benzene = the vapor pressure of pure benzene = 26.5 torr
Psolution = 0.139 * 26.5 torr
Psolution = 3.69 torr
The vapor pressure of the solution is 3.69 torr
Answer:
7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.
Explanation:
First of all the molecular weight of Na2SO4 is 142.08 gram.Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.
According to the given question we have to prepare 0.100 M solution
1000 ml of solution contain 142.08×0.1= 14.208 gram Na2SO4
1 ml of solution contain 14.208÷1000= 0.014 gram
0.5L or 500ml of solution contain 0.014×500= 7gram Na2SO4.
So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.
They all have 2 elections in the outer S orbital, and 4 electrons in the P orbitals.
Answer:
20.2 amu.
Explanation:
Let A represent isotope ²⁰X
Let B represent isotope ²²X
From the question given above, the following data were obtained:
For Isotope A (²⁰X):
Mass of A = 20
Abundance (A%) = 90%
For Isotope B (²²X):
Mass of B = 22
Abundance (A%) = 10%
Relative atomic mass (RAM) =?
The relative atomic mass (RAM) of the element can be obtained as follow:
RAM = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
RAM = [(20 × 90)/100] + [(22 × 10)/100]
RAM = 18 + 2.2
RAM = 20.2 amu
Thus, relative atomic mass (RAM) of the element is 20.2 amu
Answer:
Because the density of water is one
