The ratios of corresponding sides in the two triangles are equal.

Mathematics

2 answers:

olga55 [171]3 years ago

7 0

Answer:

∠I ≅ ∠F

Step-by-step explanation:

Since, F is common vertex in the sides GF and FE of triangle FGE and I is common vertex in the sides IJ and IH of triangle IJH.

Hence, ∠I ≅ ∠F will be the required information to prove that △FGE ~ △IJH by the SAS similarity theorem.

Alisiya [41]3 years ago

6 0

Answer:

∠I ≅ ∠F

Step-by-step explanation:

I took the test.

Got it right ;3

You might be interested in

If sinθ = -1/2 and θ is in Quadrant III, then tanθ = _____.

Gnom [1K]

Answer: $\tan \theta=\dfrac{1}{\sqrt3}.$

Step-by-step explanation: Given that

$\sin\theta=-\dfrac{1}{2}$ and $\theta$ lies in Quadrant III.

We are to find the value of $\tan \theta.$

We will be using the following trigonometric identities:

$(i)~sin^2\theta+\cos^2\theta=1,\\\\(ii)~\dfrac{\sin\theta}{\cos{\theta}}=\tan \theta.$

We have

$\tan\theta\\\\\\=\dfrac{\sin\theta}{\cos\theta}\\\\\\=\dfrac{\sin\theta}{\pm\sqrt{1-\sin^2\theta}}\\\\\\=\pm\dfrac{-\frac{1}{2}}{\sqrt{1-\left(\frac{1}{2}\right)^2}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\sqrt{1-\frac{1}{4}}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\frac{\sqrt3}{2}}\\\\\\=\pm\dfrac{1}{\sqrt3}.$